Solve: 8 - Square Root of 16 × 3 | Order of Operations Practice

$8 - \sqrt{16} \times 3 =$

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$8 - \sqrt{16} \times 3 =$

First, evaluate the square root: $\sqrt{16}=4$ .

Then, follow the order of operations (PEMDAS/BODMAS):

1. Multiplication: $4 \times 3 = 12$

2. Subtraction: $8 - 12 = -4$

So, the correct answer is $-4$ .

$-4$

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What is the result of the following equation?

$36-4\div2$

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