Solve: 2/3(12+0-5) Using Order of Operations

$\frac{2}{3}(12+0-5)=$

According to the distribution law rules, we will multiply both thirds by each term in parentheses:

$\frac{2}{3}\times12+\frac{2}{3}\times0-\frac{2}{3}\times5=$

Remember that any whole number can be written as a fraction with a denominator of 1, except for the digit 0.

Let's write the exercise in the following form:

$\frac{2}{3}\times\frac{12}{1}+\frac{2}{3}\times0-\frac{2}{3}\times\frac{5}{1}=$

We multiply numerator by numerator and denominator by denominator in each multiplication exercise.

Remember that when we multiply any number by 0, the result will be 0.

Therefore we get:

$\frac{24}{3}+0-\frac{10}{3}=$

Let's solve the first fraction exercise, and simplify the remaining fraction to get the exercise:

$8-3\frac{1}{3}=4\frac{2}{3}$