Simplify the Expression: 12⁵ ÷ 12⁸ Using Laws of Exponents

Question

Insert the corresponding expression:

125128= \frac{12^5}{12^8}=

Video Solution

Solution Steps

00:00 Simply
00:03 According to laws of exponents, division of powers with equal bases (A)
00:06 equals the same base (A) raised to the power of the difference of exponents (M-N)
00:09 We will use this formula in our exercise
00:12 We'll keep the base and subtract between the exponents
00:15 According to laws of exponents, any base (A) to the power of (-N)
00:18 equals the reciprocal number (1/A) to the opposite power (N)
00:22 We will use this formula in our exercise
00:27 And this is the solution to the question

Step-by-Step Solution

To simplify the expression 125128 \frac{12^5}{12^8} , we'll follow these steps:

  • Step 1: Apply the quotient rule for exponents.
  • Step 2: Simplify and interpret the result using negative exponents if necessary.

Let's work through each step:

Step 1: Apply the quotient rule for exponents.
We are given the expression 125128 \frac{12^5}{12^8} . According to the quotient rule for exponents, aman=amn \frac{a^m}{a^n} = a^{m-n} , so we have:

125128=1258=123 \frac{12^5}{12^8} = 12^{5-8} = 12^{-3}

Step 2: Simplify and interpret.
The result 123 12^{-3} can be expressed using the concept of negative exponents an=1an a^{-n} = \frac{1}{a^n} :

123=1123 12^{-3} = \frac{1}{12^3}

Therefore, both expressions 123 12^{-3} and 1123 \frac{1}{12^3} are equivalent.

Matching with the provided choices:
- Choice 1: 123 12^{-3} - This matches our first result.
- Choice 2: 1123 \frac{1}{12^3} - This matches our interpretation of the negative exponent.

Choice 4 states: "a'+b' are correct," which refers to both expressions being correct representations. Therefore, the correct answer is "a'+b' are correct."

Answer

a'+b' are correct