Calculate the Area of a Rectangle: Two 5-Unit Squares Combined

Question

Look at the given rectangle made of two squares below:

What is its area?

00:00 Find the area of rectangle AFCD

00:03 In a square all sides are equal

00:15 To calculate the area of the rectangle, we'll calculate the areas of the squares

00:23 To calculate the area of a square, multiply side(5) by side(5)

00:27 This is the area of the squares

00:36 Now we'll sum the areas of the squares to find the area of the rectangle

00:41 And this is the solution to the question

In a square all sides are equal, therefore we know that:

$AB=BC=CD=DE=EF=FA=5$

The area of the rectangle can be found in two ways:

Find one of the sides (for example AC)
$AC=AB+BC$
$AC=5+5=10$
and multiply it by one of the adjacent sides to it (CD/FA, which we already verified is equal to 5)
$5\times10=50$
Find the area of the two squares and add them.
The area of square BCDE is equal to the multiplication of two adjacent sides, both equal to 5.
$5\times5=25$
Square BCDE is equal to square ABFE, because their sides are equal and they are congruent.
Therefore, the sum of the two squares is equal to:
$25+25=50$