Calculate the Area of a Rectangle: Two 5-Unit Squares Combined

In a square all sides are equal, therefore we know that:

$AB=BC=CD=DE=EF=FA=5$

The area of the rectangle can be found in two ways:

1. Find one of the sides (for example AC)

   $AC=AB+BC$

   $AC=5+5=10$

   and multiply it by one of the adjacent sides to it (CD/FA, which we already verified is equal to 5)

   $5\times10=50$

2. Find the area of the two squares and add them.

   The area of square BCDE is equal to the multiplication of two adjacent sides, both equal to 5.

   $5\times5=25$

   Square BCDE is equal to square ABFE, because their sides are equal and they are congruent.

   Therefore, the sum of the two squares is equal to:

   $25+25=50$