Special Cases (0 and 1, Inverse, Fraction Line): Using fractions

According to the order of operations, we will first solve the fraction exercise:

$\frac{20}{3+2}=\frac{20}{5}=4$

$4+6=10$

According to the order of operations, we will first solve the fraction exercise:

$\frac{16-10}{2}=\frac{6}{2}=3$

$20-3=17$

Let's first refer to the numerator of the fraction, we'll convert it to an addition exercise of two fractions:

$1+\frac{1}{2}$

$1=\frac{2}{2}$

Now we get:

$\frac{\frac{2}{2}+\frac{1}{2}}{6}=$

$\frac{\frac{2+1}{2}}{6}=$

$\frac{\frac{3}{2}}{\frac{6}{1}}=$

Let's multiply the two fractions - numerator by numerator and denominator by denominator:

$\frac{1\times3}{2\times6}=$

$\frac{3}{12}=\frac{3}{3\times4}$

Let's simplify:

$\frac{3}{3\times4}=\frac{1}{4}$

$\frac{1}{4}=0.25$