Special Cases (0 and 1, Inverse, Fraction Line): Using negative numbers

We begin by addressing the numerator of the fraction.

First we solve the division exercise and the exercise within the parentheses:

$400:(-5)=-80$

$(93-61)=32$

We obtain the following:

$\frac{-80-(-2\times32)}{4}=$

We then solve the parentheses in the numerator of the fraction:

$\frac{-80-(-64)}{4}=$

Let's remember that a negative times a negative equals a positive:

$\frac{-80+64}{4}=$

$\frac{-16}{4}=-4$

Initially, we address the first parentheses in the numerator of the fraction:

$(15\times8+15)=$

According to the rules, we first must solve the multiplication exercise and then the addition:

$120+15=135$

We obtain the following exercise:

$\frac{(135:27+45)\times8:20}{-5}=$

We will again address the parentheses in the numerator of the fraction. First by solving the division and then addition exercise.

$5+45=50$

We are left with the following exercise:

$\frac{50\times8:20}{-5}=$

We divide 50 into a multiplication exercise:

$\frac{5\times10\times8:20}{-5}=$

We then simplify:

$-10\times8:20=$

Lastly we solve from left to right:

$-80:20=-4$

We begin by solving the two parentheses in the numerator of the fraction:

$(32\times4+8)=128+8=136$

$(-27+35)=8$

We obtain the following exercise:

$\frac{136:8}{-2}=$

$\frac{17}{-2}=-8.5$