Special Cases (0 and 1, Inverse, Fraction Line): Using 1

According to the order of operations, we first place the multiplication operation inside parenthesis:

$(7\times1)+\frac{1}{2}=$

Then, we perform this operation:

$7\times1=7$

Finally, we are left with the answer:

$7+\frac{1}{2}=7\frac{1}{2}$

According to the order of operations, we first solve the expression in parentheses:

$5\times1=5$

Now we multiply:

$8\times5=40$

According to the order of operations, we will solve the exercise from left to right since it only contains multiplication and division operations:

$\frac{6}{3}=2$

$2\times1=2$

According to the rules of the order of operations we should begin by placing the multiplication exercise within parentheses:

$18-(1\times0.1)=$

We then proceed solve the multiplication exercise:

$1\times0.1=0.1$

And we should obtain the following exercise:

$18-0.1=17.9$

According to the order of operations, first put the multiplication operation in parenthesis:

$18+(2\times1)=\text{ ?}$

Then solve the exercise inside the parenthesis:

$2\times1=2$

Which leaves us with:

$18+2=20$

According to the order of operations, we will solve the exercise from left to right since there is only multiplication in the exercise:

$18\times1=18$

$18\times10=180$

According to the rules of the order of operations, we should first solve the exercise from left to right since there are only multiplication and division operations present:

$1\times\frac{1}{2}=\frac{1}{2}$

$\frac{1}{2}:2=\frac{1}{4}$

According to rules of the order of operations , we must first place the multiplication exercise inside of parentheses:

$6+(8.4\times1)=$

Let's now proceed to solve the said expression:

$8.4\times1=8.4$

We should obtain the following exercise:

$6+8.4=14.4$

According to the order of operations in arithmetic we should begin by placing the division operation inside of parentheses:

$(8:1)+2=$

Let's now proceed to solve the said problem:

$8:1=8$

We should obtain the following expression:

$8+2=10$

According to the order of operations, we must first solve the expression inside of the parentheses:

$7\times1=7$

Resulting in the following expression:

$8\times7=56$

According to the order of operations, we must solve the exercise from left to right since it contains only multiplication operations:

$\frac{3}{2}\times1=\frac{3}{2}$

$\frac{3}{2}\times\frac{1}{3}=$

Then, we will multiply the 3 by 3 to get:

$\frac{1}{2}\times1=\frac{1}{2}$

According to the order of operations rules, we must first solve the fraction:

$\frac{6}{3}=2$

Resulting in the following expression:

$2-1=1$

According to the order of operations, we solve the exercise from left to right since there is only multiplication in the exercise:

$20\times1=20$

$20\times8=160$