221+?=4
\( 2\frac{1}{2}+?=4 \)
\( ?-2\frac{1}{3}=1\frac{2}{4} \)
\( ?-2\frac{1}{4}=5\frac{2}{4} \)
\( 3\frac{2}{3}+?=6 \)
\( ?-4\frac{1}{7}=1\frac{3}{7} \)
\( 5\frac{2}{7}+?=6\frac{3}{7} \)
\( 5\frac{3}{4}+?=7\frac{1}{2} \)
\( ?-5\frac{5}{6}=1\frac{2}{3} \)