Examples with solutions for Graphical Representation: Using additional geometric shapes

Exercise #1

Calculate the slope of the line that forms a right triangle with the axis x and the axis y and passes through the points (5,0),(0,5) (5,0),\lparen0,-5) .

Video Solution

Step-by-Step Solution

To solve this problem, we will calculate the slope of the line passing through the given points:

  • Step 1: Identify coordinates: The points are (5,0)(5, 0) and (0,5)(0, -5).
  • Step 2: Use the slope formula: m=y2y1x2x1 m = \frac{y_2 - y_1}{x_2 - x_1} Substituting the coordinates, we have: m=5005 m = \frac{-5 - 0}{0 - 5}
  • Step 3: Simplify the expression: m=55=1 m = \frac{-5}{-5} = 1

Thus, the slope of the line is 11.

Therefore, the solution to the problem is 11.

Answer

1

Exercise #2

Calculate the slope of the line that creates a right triangle with the x and y axes and passes through the points B(5,0),A(0,10) B(5,0),A\lparen0,10) .

Video Solution

Step-by-Step Solution

To solve this problem, we'll determine the slope of the line that passes through the points A(0,10) A(0, 10) and B(5,0) B(5, 0) . The slope of a line passing through two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by:

m=y2y1x2x1 m = \frac{y_2 - y_1}{x_2 - x_1} .

We identify the coordinates of our points:

  • (x1,y1)=(5,0) (x_1, y_1) = (5, 0)
  • (x2,y2)=(0,10) (x_2, y_2) = (0, 10) .

Substitute these coordinates into the slope formula:

m=10005 m = \frac{10 - 0}{0 - 5} .

Simplifying the equation gives:

m=105=2 m = \frac{10}{-5} = -2 .

Thus, the slope of the line is 2 -2 .

Therefore, the solution to the problem is m=2 m = -2 .

Answer

2 -2

Exercise #3

Two straight lines are drawn with the x axis and the y triangle axis.

The first line passes through the points (4,0),(0,2) (4,0),(0,2)

The second line passes through the points (0,6),(4,0) (0,-6),(4,0)

Find the slope of each line.

Video Solution

Step-by-Step Solution

To determine the slopes of the two lines, we will use the slope formula:

  • Slope Formula: m=y2y1x2x1 m = \frac{y_2 - y_1}{x_2 - x_1}

Let's start with the first line:

Line I:

The points are (4,0)(4, 0) and (0,2)(0, 2). Applying the slope formula:

m1=2004=24=12 m_1 = \frac{2 - 0}{0 - 4} = \frac{2}{-4} = -\frac{1}{2}

Thus, the slope of Line I is 12 -\frac{1}{2} .

Now, let's calculate the slope for the second line:

Line II:

The points are (0,6)(0, -6) and (4,0)(4, 0). Applying the slope formula:

m2=0(6)40=64=32 m_2 = \frac{0 - (-6)}{4 - 0} = \frac{6}{4} = \frac{3}{2}

Therefore, the slope of Line II is 32 \frac{3}{2} .

In conclusion, the slopes are as follows:

32=II , 12=I \frac{3}{2} = II \text{ , } -\frac{1}{2} = I .

The solution matches choice Choice 3 \text{Choice 3} .

The correct answer to the problem is: 32=II,12=I \frac{3}{2} = II, -\frac{1}{2} = I .

Answer

32=II , -12=I \frac{3}{2}=II\text{ , -}\frac{1}{2}=I

Exercise #4

A straight line is drawn between the y axis and the straight line y=2 y=-2 to create a triangle.


The line passes through the points B(5,2),A(0,0) B(5,-2),A\lparen0,0) .

Calculate the slope of the line.

Video Solution

Step-by-Step Solution

To solve this problem, we'll calculate the slope using the slope formula:

  • Step 1: Identify the coordinates of the points. We have point A(0,0) A(0, 0) and point B(5,2) B(5, -2) .
  • Step 2: Apply the slope formula m=y2y1x2x1 m = \frac{y_2 - y_1}{x_2 - x_1} .
  • Step 3: Substitute the coordinates: (x1,y1)=(0,0)(x_1, y_1) = (0, 0) and (x2,y2)=(5,2)(x_2, y_2) = (5, -2).

Now, let's work through each step:

The slope formula is:
m=y2y1x2x1=2050 m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-2 - 0}{5 - 0} .

This simplifies to:
m=25 m = \frac{-2}{5} .

Therefore, the solution to the problem is m=25 m = -\frac{2}{5} .

The correct answer choice is 25 -\frac{2}{5} .

Answer

25 -\frac{2}{5}

Exercise #5

A straight line is a diagonal squared.

The line passes through the points (8,3),(2,7) (8,3),(2,7) .

Choose the equation that corresponds to the line.

Video Solution

Step-by-Step Solution

To find the equation of the line passing through the points (8,3) (8,3) and (2,7) (2,7) , follow these steps:

  • Step 1: Calculate the slope m m .
  • Step 2: Use the slope and one of the points to solve for the y-intercept b b .
  • Step 3: Write the equation of the line in the form y=mx+b y = mx + b .

Step 1: Calculate the slope m m . The slope m m is given by the formula:

m=y2y1x2x1=7328=46=23 m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{7 - 3}{2 - 8} = \frac{4}{-6} = -\frac{2}{3} .

Step 2: With the slope known, use one point (for example, (8,3) (8,3) ) to find b b in the slope-intercept form y=mx+b y = mx + b . Substitute the values:

3=23(8)+b 3 = -\frac{2}{3}(8) + b .

This simplifies to:

3=163+b 3 = -\frac{16}{3} + b .

Add 163\frac{16}{3} to both sides to solve for b b :

b=3+163=93+163=253 b = 3 + \frac{16}{3} = \frac{9}{3} + \frac{16}{3} = \frac{25}{3} .

Step 3: Write the equation using the calculated slope and y-intercept:

y=23x+253 y = -\frac{2}{3}x + \frac{25}{3} .

To express it as a mixed number, 253 \frac{25}{3} is 813 8\frac{1}{3} , so:

y=23x+813 y = -\frac{2}{3}x + 8\frac{1}{3} .

Thus, the correct equation of the line is y=23x+813 y = -\frac{2}{3}x + 8\frac{1}{3} , which corresponds to choice 3.

The final answer is: y=23x+813 y = -\frac{2}{3}x + 8\frac{1}{3} .

Answer

y=23x+813 y=-\frac{2}{3}x+8\frac{1}{3}

Exercise #6

A straight line is drawn forming a triangle with the x and y axes.

The line passes through the points (0,6),(4,0) (0,-6),(4,0) .

Choose the equation that represents the line.

Video Solution

Step-by-Step Solution

Let's derive the equation of the line:

  • Step 1: Calculate the Slope
    The slope m m of a line through two points (x1,y1) (x_1, y_1) and (x2,y2) (x_2, y_2) is computed as follows: m=y2y1x2x1 m = \frac{y_2 - y_1}{x_2 - x_1} Substituting the given points (0,6) (0, -6) and (4,0) (4, 0) : m=0(6)40=64=32 m = \frac{0 - (-6)}{4 - 0} = \frac{6}{4} = \frac{3}{2} Hence, the slope of the line is 32 \frac{3}{2} .

  • Step 2: Write the Equation Using the Slope-Intercept Form
    The slope-intercept form is: y=mx+b y = mx + b Where m m is the slope and b b is the y-intercept. Since the line passes through (0,6) (0, -6) , this point is the y-intercept (b=6 b = -6 ). Thus, we have: } y=32x6 y = \frac{3}{2}x - 6

Therefore, the equation of the line is y=32x6 y = \frac{3}{2}x - 6 .

The correct choice is option 4.

Answer

y=32x6 y=\frac{3}{2}x-6