Examples with solutions for Angles in Parallel Lines: Using angles in a triangle

Exercise #1

ABC is an isosceles triangle.

AB = AC

Angle B equals 55 degrees.

Find the value X.

555555XXXAAABBBCCC

Video Solution

Step-by-Step Solution

Since this is an isosceles triangle, angle B and angle C are equal to each other.

B=C=55 B=C=55

Therefore we can calculate angle A since the sum of the angles in the triangle equals 180:

A=1805555=180110=70 A=180-55-55=180-110=70

Since angle X is the vertex of angle A, they are equal, hence:

A=X=70 A=X=70

Answer

70 70

Exercise #2

The angles below are between parallel lines.

XXX535353949494

What is the value of X?

Video Solution

Step-by-Step Solution

Our initial objective is to find the angle adjacent to the 94 angle.

Bearing in mind that adjacent angles are equal to 180, we can calculate the following:

18094=86 180-94=86
Let's now observe the triangle.

Considering that the sum of the angles in a triangle is 180, we can determine the following:

180=x+53+86 180=x+53+86

180=x+139 180=x+139

180139=x 180-139=x

x=41 x=41

Answer

41°

Exercise #3

Lines a and b are parallel.

What is the size of angle α \alpha ?

aaabbb6254α

Video Solution

Step-by-Step Solution

Please note that according to the definition of corresponding angles, the angle α \alpha corresponds to the angle located on line a and is also within the small triangle created in the drawing.

As we already have one angle in this triangle, we will try to find and calculate the remaining angles.

Furthermore the angle opposite to the angle 62 next to the vertex is also equal to 62 (vertex opposite angles are equal to one other)

Therefore, we can now calculate the missing angle in the small triangle created in the drawing, which is the angle

α \alpha

α=1805462 \alpha=180-54-62

α=64 \alpha=64

Answer

64

Exercise #4

110110110105105105XXX

What is the value of X given the angles between parallel lines shown above?

Video Solution

Step-by-Step Solution

Due to the fact that the lines are parallel, we will begin by drawing a further imaginary parallel line that crosses the 110 angle.

The angle adjacent to the angle 105 is equal to 75 (a straight angle is equal to 180 degrees) This angle is alternate with the angle that was divided using the imaginary line, therefore it is also equal to 75.

In the picture we are shown that the whole angle is equal to 110. Considering that we found only a part of it, we will indicate the second part of the angle as X since it alternates and is equal to the existing X angle.

Therefore we can say that:

75+x=100 75+x=100

x=11075=35 x=110-75=35

Answer

35°

Exercise #5

Look at the angles formed by parallel lines in the figure below:

646464XXX757575

What is the value of X?

Video Solution

Step-by-Step Solution

Given that the three lines are parallel:

The 75 degree angle is an alternate angle with the one adjacent to angle X on the right side, and therefore is also equal to 75 degrees.

The 64 degree angle is an alternate angle with the one adjacent to angle X on the left side, and therefore is also equal to 64 degrees.

Now we can calculate:

64+x+75=180 64+x+75=180

x=1807564=41 x=180-75-64=41

Answer

41°

Exercise #6

Lines a and b are parallel.

What is the size of angle α \alpha ?

aaabbb120α

Video Solution

Step-by-Step Solution

First, let's draw another line parallel to the existing lines that will divide the given angle of 120 degrees in the following way:

aaabbb120α

Note that the line we drew creates two adjacent and straight angles, each equal to 90 degrees.

Now we can calculate the missing part of the angle known to us using the formula:

12090=30 120-90=30

Let's write down the known data as follows:

aaabbbα30

Note that from the drawing we can see that angle alpha and the angle equal to 30 degrees are alternate angles, therefore they are equal to each other.

α=30 \alpha=30

Answer

30

Exercise #7

Calculate the value of X according to the diagram.

XXX66

Video Solution

Answer

66 66

Exercise #8

ABC is an isosceles triangle.

Calculate the value of X.

XXXAAABBBCCC32

Video Solution

Answer

Impossible to find

Exercise #9

ABC triangle

Calculate the value of X

AAABBBCCC30X70

Video Solution

Answer

70 70

Exercise #10

ABC is a triangle.

AB = AC

Angle C1 is equal to 22°.

Calculate the size of angle B2.

AAABBBCCC12123

Video Solution

Answer

22 22 °

Exercise #11

DE is parallel to BC.

Calculate angles C and B using the data in the diagram below.

AAABBBCCCDDDEEE654075

Video Solution

Answer

B=75,C=65 B=75,C=65

Exercise #12

ABC is a triangle.

Calculate the size of internal angle A.

AAABBBCCC130110

Video Solution

Answer

60 60

Exercise #13

Calculate the value of X and Y according to the data given in the diagram.

XXXYYY70707070

Video Solution

Answer

X=70,Y=40 X=70,Y=40

Exercise #14

ABC is a triangle.

Angle C2 is equal to 20°.

Angle C3 is equal to 80°.

Calculate the size of angles A2 and B2.

BBBAAACCC1212123

Video Solution

Answer

A2=80,B2=80 A2=80,B2=80

Exercise #15

Calculate the value of X according to the data in the figure.

3377X

Video Solution

Answer

70 70

Exercise #16

b || a

Calculate x.

aaabbb2475x-15

Video Solution

Answer

66

Exercise #17

a,b parallel

Find X

aaabbb

Video Solution

Answer

21.26

Exercise #18

Line a is parallel to line b.

Calculate X.

aaabbb4x-710x8x+5

Video Solution

Answer

12

Exercise #19

a,b parallel

Find X by means of Y

4y+284y+284y+28767676xxxaaabbb

Video Solution

Answer

4y-48

Exercise #20

Three parallel lines are drawn forming the angles shown in the diagram below.

646464XXX999999

What is the value of X?

Video Solution

Answer

35°