Area of a Deltoid - Examples, Exercises and Solutions

Let's begin by reminding ourselves of the formula for the area of a kite

$\frac{Diagonal1\times Diagonal2}{2}$

Both these values are given to us in the figure thus we can insert them directly into the formula:

(4*7)/2

28/2

14

To solve the exercise, we first need to know the formula for calculating the area of a kite:

It's also important to know that a concave kite, like the one in the question, has one of its diagonals outside the shape, but it's still its diagonal.

Let's now substitute the data from the question into the formula:

(6*5)/2=
30/2=
15

To solve the exercise, we first need to remember how to calculate the area of a rhombus:

(diagonal * diagonal) divided by 2

Let's plug in the data we have from the question

10*6=60

60/2=30

And that's the solution!

First, let's recall the formula for the area of a rhombus:

(Diagonal 1 * Diagonal 2) divided by 2

Now we will substitute the known data into the formula, giving us the answer:

(12*16)/2
192/2=
96

First, we recall the formula for the area of a kite: multiply the lengths of the diagonals by each other and divide the product by 2.

We substitute the known data into the formula:

 $\frac{8\cdot DB}{2}=32$

We reduce the 8 and the 2:

$4DB=32$

Divide by 4

$DB=8$

To solve the problem, we need to remember the formula for the area of a rhombus:

The product of the diagonals multiplied together and then divided by 2.

Let's substitute in our data into the formula:

(8*X) = 60
2

Note that we can simplify the fraction, thus eliminating the denominator:

4X = 60

Let's finally divide the equation by 4 to get our answer:

X = 15

We substitute the data we have into the formula for the area of the kite:

$S=\frac{AC\times BD}{2}$

$42=\frac{AC\times14}{2}$

We multiply by 2 to remove the denominator:

 $14AC=84$

Then divide by 14:

$AC=6$

In a rhombus, the main diagonal crosses the second diagonal, therefore:

$AO=\frac{AC}{2}=\frac{6}{2}=3$

To solve the question, we first need to remember the formula for the area of a kite:

Diagonal * Diagonal / 2

This means that if we substitute the given data we can see that:

a(2a+2)/2 = area of the kite

Let's remember that we are also given the area, so we'll put that in the equation too

a(2a+2)/2 = 6a

Now we have an equation that we can easily solve.

First, let's get rid of the fraction, so we'll multiply both sides of the equation by 2

a(2a+2)=6a*2
a(2a+2)=12a

Let's expand the parentheses on the left side of the equation

2a²+2a=12a

2a²=10a

Let's divide both sides of the equation by a

2a=10

Let's divide again by 2

a=5

And that's the solution!

We can calculate the area of rectangle ABCD as follows:

$20\times30=600$

Now let's divide the deltoid along its length and width and add the following points:

Finally, we can calculate the area of deltoid PMNK as follows:

$PMNK=\frac{PN\times MK}{2}=\frac{20\times30}{2}=\frac{600}{2}=300$

Given the problem, we are tasked to find the value of $x$ for a deltoid where the length is twice the width and the area is given. Let's proceed as follows:

• Step 1: In this deltoid problem, the diagonals correspond to length $2x$ and width $x$. The formula for the area of a deltoid in terms of its diagonals is $A = \frac{1}{2} \times d_1 \times d_2$.
• Step 2: Substitute the values. Thus, the area $16 = \frac{1}{2} \times (2x) \times x$.
• Step 3: Simplify the equation: $16 = \frac{1}{2} \times 2x^2 = x^2$.
• Step 4: Solve for $x$: We find $x^2 = 16$, so $x = \sqrt{16}$.
• Step 5: Conclude $x = 4$.

Therefore, the solution to the problem is $x = 4$.