Vertical Multiplication Practice Problems & Worksheets

To solve the multiplication problem $64 \times 6$, we'll perform the following steps:

• Step 1: Break down $64$ into tens and units. So, $64$ can be written as $60 + 4$.
• Step 2: Multiply each component separately by $6$.
• Step 3: Calculate $60 \times 6$ and $4 \times 6$ separately.
• Step 4: Sum the results of the above calculations to find the total product.

Now, let's execute these steps specifically:

Step 1: Represent $64$ as $60 + 4$. This simplifies the multiplication process.

Step 2: Multiply the tens: $60 \times 6 = 360$.

Step 3: Multiply the units: $4 \times 6 = 24$.

Step 4: Now, add the two results: $360 + 24 = 384$.

Therefore, the product of $64 \times 6$ is $384$.

To solve this multiplication problem, follow these clear steps:

• Step 1: Align the numbers vertically (place 26 above 6), ensuring the digits are properly arranged by place value.
• Step 2: Begin multiplication with the unit digit of the bottom number (6). Multiply 6 by each digit in 26, starting from the right.

Now, let's perform the calculations:

Step 1: Multiply the units digit of 6 with the number 26:
- $6 \times 6 = 36$. Write 6 in the units place of the answer, and carry over the 3.
- Next, multiply $6 \times 2 = 12$. Then, add the carryover (3) to 12, resulting in 15.

Step 2: Write 15 next to the 6 in the result. Thus, the complete multiplication gives 156.

Therefore, the solution to the problem is $\boxed{156}$.

To solve this multiplication problem, we will perform the following steps:

• Step 1: Write the two-digit number 19 as the sum of its place values: 19 = 10 + 9.
• Step 2: Multiply the first term (10) by 6: $10 \times 6 = 60$.
• Step 3: Multiply the second term (9) by 6: $9 \times 6 = 54$.
• Step 4: Add the results of the two multiplications: $60 + 54 = 114$.

Therefore, the product of 19 and 6 is $\textbf{114}$.

To solve this multiplication problem, we will use the vertical multiplication method:

• Step 1: Multiply the ones digit of the first number by the second number.
• Here, multiply $3 \times 7 = 21$. Record the 1 in the ones place and carry over the 2.
• Step 2: Multiply the tens digit of the first number by the second number, and add any carried over value from the first step.
• Calculate $7 \times 7 = 49$. Add the carry-over of 2 to this result, which gives $49 + 2 = 51$.
• Write the 51 on top of where we placed our previous result, so it becomes 5 at the tens and hundreds position.

Therefore, the final multiplied value is $511$.

The correct answer choice is option 4: $511$.

To solve this multiplication problem, we will use vertical multiplication:

• Step 1: Write down the multiplication in the vertical form:
         $96$
  $\times$     $3$
  $\_\_\_\_\_\_\_\_$
• Step 2: Multiply the one's digit of the bottom number (3) by the one's digit of the top number:\
  3 \times 6 = 18. Write 8 in the one's place and carry over 1 to the next place.
• Step 3: Multiply the tens digit of the top number (9) by 3:
  3 \times 9 = 27. Add the carryover 1, getting 28. Write 28 in the tens and hundreds places.
• Step 4: Write down the results:
       $288$

Therefore, the product of $96 \times 3$ is $288$.

Hence, the correct answer is choice $288$.