To solve this problem, we'll perform the multiplication of 560 by 63 using the vertical multiplication method, which involves two main calculations:
Now, let's perform the calculations:
Step 1: Multiply 560 by 3:
Step 2: Multiply 560 by 60 (which is 10 times 6):
First, multiply 560 by 6:
Since we're actually multiplying by 60, we append a zero to the product (equivalent to multiplying by 10):
Step 3: Add the results from steps 1 and 2:
Therefore, the product of 560 and 63 is .
To solve this problem, we'll multiply by through the following steps:
The solution is therefore .
To solve this problem, we will multiply 430 by 11 using vertical multiplication:
Step 1: Multiply 430 by 1 (the ones place of 11).
430 multiplied by 1 is 430. Let's write this down while aligning according to place value, i.e., 430.
Step 2: Multiply 430 by 10 (the tens place of 11).
To do this, multiply 430 by 1 and shift the result one place to the left, adding a zero at the end. Thus, 430 multiplied by 10 is 4300.
Step 3: Add the results from step 1 and step 2.
Align the numbers:
430
+ 4300
--------
4730
Therefore, the product of 430 and 11 is .
The correct answer is 4730, which corresponds to choice 2.
To solve the multiplication problem of 161 and 12, follow these steps:
Therefore, the product of 161 and 12 is .
To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: Multiply by .
Step 2: Multiply by (considering the tens place value, this is actually multiplying by ).
Step 3: Add the two products together.
Therefore, the solution to the problem is .
To solve this problem, we'll perform vertical multiplication of by as follows:
Step 1: Multiply by (the units digit of ):
Step 2: Multiply by (the tens digit of ), remembering that this is in the tens place:
Step 3: Add the two results from Steps 1 and 2:
Therefore, the product of and is , which corresponds to choice (2).
To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: Multiply .
.
Step 2: Multiply the result by since we're considering .
.
Therefore, the solution to the problem is .
To solve this problem, we'll follow these steps:
Multiply by the unit digit of , which is .
Multiply by the tens digit of , which is .
Add the resulting products, considering place values.
Now, let's carry out the multiplication step-by-step:
Step 1: Multiply by . This gives . Write this result as the first partial product.
Step 2: Multiply by . This gives . Since this is a tens digit multiplication, place this result one position to the left, resulting in .
Step 3: Add the partial products:
Therefore, the product .
The correct answer is .
To solve this problem, we'll multiply the two numbers 341 and 22 using the vertical multiplication technique.
Therefore, the solution to the problem is .
Let's solve this multiplication problem step by step:
Therefore, the solution to the problem is .
To solve this problem, we will use the vertical multiplication method for multiplying the numbers 102 and 25.
First, multiply 5 by 2 (the units digit of 102):
. Write down 0 and carry over 1.
Next, multiply 5 by 0 (the tens digit of 102) and add the carry-over:
. Write down 1.
Finally, multiply 5 by 1 (the hundreds digit of 102):
. The result is 510.
Because this is the tens place, we write a zero beneath the 0 from our previous calculation (indenting by one place to the left).
Multiply 2 by 2:
. Write down 4.
Next, multiply 2 by 0:
. Write down 0.
Finally, multiply 2 by 1:
. The result is 2040. Place this beneath the 510, indented correctly.
The sum is 2550. Thus, the product of 102 and 25 is .
Therefore, the solution to the problem is .
To solve the multiplication problem for , we will calculate it directly through division.
Our problem states:
We can isolate by dividing both sides of the equation by :
Calculating the division, we find:
The correct solution is therefore . This corresponds to choice 1, which is the answer given as .
To solve the problem, we need to multiply 142 by 16 using vertical multiplication:
Start by multiplying the units digit of 16 (which is 6) by 142:
Then, multiply the tens digit of 16 (which is 1, but placed in the tens position, effectively being 10) by 142:
Now, add these two results together:
Thus, the result of multiplying 142 by 16 is .
Therefore, the solution to the problem is .
To solve the multiplication of and , we will use vertical multiplication:
126 × 7 ----- 882This yields .
126 ×10 ----- 1260This results in .
Therefore, the final product of is .
To solve the problem of multiplying , follow these steps:
Thus, the solution to the multiplication is .
To solve this problem, we'll find the product of 191 and 20 using vertical multiplication.
Here are the detailed steps:
Therefore, the solution to the problem is , which corresponds to choice 3 in the provided list.
To solve this multiplication problem, 133 multiplied by 19, using long multiplication, follow these steps:
Therefore, the product of 133 and 19 is .
To solve this problem, follow these steps:
Step 1: Multiply 111 and 70 using vertical multiplication.
Step 2: Confirm the calculation by reviewing each step of the multiplication process.
Let's begin:
Step 1: Vertical Multiplication
We'll perform the multiplication of 111 by 70 using vertical multiplication:
Explanation:
- We multiply 111 by 0 from 70, giving 0.
- We then multiply 111 by 7 (tens digit of 70). Add a zero to the result of this step to account for its place value:
Step 2: Verify the Calculation
By verifying each multiplication step and ensuring correct place value management, the calculation confirms that the product is indeed 7770.
Therefore, the solution to the problem is .
To solve this problem, we will use vertical multiplication. Let's break this down into clear steps:
Step 1: Multiply 120 by 1:
Step 2: Multiply 120 by 3:
Since this multiplication is coming from the tens place, we add a zero, resulting in 3600.
Step 3: Add the results from Step 1 and Step 2:
Therefore, the product of and is .
To solve this problem, we'll use vertical multiplication:
Therefore, the product of 131 and 61 is .
This matches choice 3 in the given options.