The Vertex of the Parabola: Finding a stationary point

Examples with solutions for The Vertex of the Parabola: Finding a stationary point

Exercise #1

The following function has been graphed below:

f(x)=x28x+16 f(x)=x^2-8x+16

Calculate point C.

CCC

Video Solution

Step-by-Step Solution

To solve the exercise, first note that point C lies on the X-axis.

Therefore, to find it, we need to understand what is the X value when Y equals 0.

 

Let's set the equation equal to 0:

0=x²-8x+16

We'll use the preferred method (trinomial or quadratic formula) to find the X values, and we'll discover that

X=4

 

Answer

(4,0) (4,0)

Exercise #2

The following function has been graphed below.

f(x)=x2+5x+6 f(x)=-x^2+5x+6

Calculate point C.

BBBAAACCC

Video Solution

Step-by-Step Solution

To solve the question, let's recall the formula for finding the vertex of a parabola:

Let's substitute the known data into the formula:

-5/2(-1)=-5/-2=2.5

In other words, the x-coordinate of the vertex of the parabola is found when the X value equals 2.5,

Now let's substitute this into the parabola equation and find the Y value

-(2.5)²+5*2.5+6= 12.25

Therefore, the coordinates of the vertex of the parabola are (2.5,12.25).

Answer

(212,1214) (2\frac{1}{2},12\frac{1}{4})

Exercise #3

The following function has been graphed below:

f(x)=x26x f(x)=x^2-6x

Calculate point C.

CCCAAABBB

Video Solution

Answer

(3,9) (3,-9)

Exercise #4

The following function has been graphed below.

f(x)=x26x+8 f(x)=x^2-6x+8

Calculate point B.

BBB

Video Solution

Answer

(3,1) (3,-1)