Examples with solutions for Square Root Quotient Property: Using variables

Exercise #1

Solve the following exercise:

25x2x2= \frac{\sqrt{25x^2}}{\sqrt{x^2}}=

Video Solution

Step-by-Step Solution

Express the definition of root as a power:

an=a1n \sqrt[n]{a}=a^{\frac{1}{n}}

Remember that in a square root (also called "root to the power of 2") we don't write the root's power:

n=2 n=2

meaning:

a=a2=a12 \sqrt{a}=\sqrt[2]{a}=a^{\frac{1}{2}}

Proceed to convert the expression using the root definition we mentioned above:

25x2x2=(25x2)12(x2)12 \frac{\sqrt{25x^2}}{\sqrt{x^2}}=\frac{(25x^2)^{\frac{1}{2}}}{(x^{2)^{\frac{1}{2}}}}

Now let's recall two laws of exponents:

a. The law of exponents for a power applied to a product inside of parentheses:

(ab)n=anbn (a\cdot b)^n=a^n\cdot b^n

b. The law of exponents for a power of a power:

(am)n=amn (a^m)^n=a^{m\cdot n}

Let's apply these laws to the numerator and denominator of the fraction in the expression that we obtained in the last step:

(25x2)12(x2)12=2512(x2)12(x2)12=2512x212x212 \frac{(25x^2)^{\frac{1}{2}}}{(x^{2)^{\frac{1}{2}}}}=\frac{25^{\frac{1}{2}}\cdot(x^2)^{\frac{1}{2}}}{(x^2)^{\frac{1}{2}}}=\frac{25^{\frac{1}{2}}x^{2\cdot\frac{1}{2}}}{x^{2\cdot\frac{1}{2}}}

In the first stage we applied the above law of exponents mentioned in a' and then proceeded to apply the power to both factors of the product inside of the parentheses in the fraction's numerator.

We carried this out carefully by using parentheses given that one of the factors in the parentheses is already raised to a power. In the second stage we applied the second law of exponents mentioned in b' to the second factor in the product in the fraction's numerator and similarly to the factor in the fraction's denominator,

Let's simplify all of the expressions that we obtained:

2512x212x212=25x22x22=5x1x1 \frac{25^{\frac{1}{2}}x^{2\cdot\frac{1}{2}}}{x^{2\cdot\frac{1}{2}}}=\frac{\sqrt{25}x^{\frac{2}{2}}}{x^{\frac{2}{2}}}=\frac{5x^1}{x^1}

In the first stage we converted the fraction's power back to a root. For the first factor in the product, this was done using the definition of root as a power mentioned at the beginning of the solution (in the opposite direction)

We then proceeded to calculate the numerical value of the root.

Additionally - we calculated the product of the power of the second factor in the product in the fraction's numerator in the expression that we obtained. Similarly we carried this out for the factor in the fraction's denominator. We then simplified the resulting fraction for that factor.

Let's complete the calculation and simplify the resulting fraction:

5x1x1=5=5 \frac{5x^1}{x^1} =\frac{5\not{x}}{\not{x}}=5

Let's summarize the steps of the solution thus far, as seen below:

25x2x2=(25x2)12(x2)12=5x1x1=5 \frac{\sqrt{25x^2}}{\sqrt{x^2}}=\frac{(25x^2)^{\frac{1}{2}}}{(x^{2)^{\frac{1}{2}}}} =\frac{5x^1}{x^1} =5

Therefore the correct answer is answer c.

Answer

5 5

Exercise #2

Solve the following exercise:

49x2x= \frac{\sqrt{49x^2}}{x}=

Video Solution

Step-by-Step Solution

Express the following root as a power:

an=a1n \sqrt[n]{a}=a^{\frac{1}{n}}

Remember that in a square root (also called "root to the power of 2") we don't write the root's power as shown

n=2 n=2

Meaning:

a=a2=a12 \sqrt{a}=\sqrt[2]{a}=a^{\frac{1}{2}}

Let's return to the problem and use the root definition that we mentioned above to convert the root in the fraction's numerator:

49x2x=(49x2)12x \frac{\sqrt{49x^2}}{x}=\frac{(49x^2)^{\frac{1}{2}}}{x}

Remember the two following laws of exponents:

a. The law of exponents for a power applied to a product inside of parentheses:

(ab)n=anbn (a\cdot b)^n=a^n\cdot b^n

b. The law of exponents for a power of a power:

(am)n=amn (a^m)^n=a^{m\cdot n}

Let's apply these laws to the fraction's numerator in the expression that we obtained in the last step:

(49x2)12x=4912(x2)12x=4912x212x \frac{(49x^2)^{\frac{1}{2}}}{x}=\frac{49^{\frac{1}{2}}\cdot(x^2)^{\frac{1}{2}}}{x}=\frac{49^{\frac{1}{2}}x^{2\cdot\frac{1}{2}}}{x}

In the first stage we applied the above-mentioned law of exponents noted in a' and then proceeded to applythe power to both factors of the product (in parentheses) in the fraction's numerator. We we careful to use parentheses given that one of the factors in the parentheses is already raised to a power.

In the second stage we applied the second law of exponents mentioned in b' to the second factor in the product,

Let's simplify the expression that we obtained:

4912x212x=49x22x=7x1x \frac{49^{\frac{1}{2}}x^{2\cdot\frac{1}{2}}}{x}=\frac{\sqrt{49}x^{\frac{2}{2}}}{x}=\frac{7x^1}{x}

In the first stage we converted the fraction's power back to a root, for the first factor in the product, using the definition of root as a power mentioned at the beginning of the solution ( in the opposite direction)

Additionally- we calculated the product in the exponent of the second factor in the product in the fraction's numerator in the expression that we obtained. We then we simplified the resulting fraction.

Finish the calculation and proceed to simplify the resulting fraction:

7x1x=7=7 \frac{7x^1}{x}=\frac{7\not{x}}{\not{x}}=7

Let's summarize the various steps of the solution that we obtained thus far, as shown below:

49x2x=(49x2)12x=4912x212x=7 \frac{\sqrt{49x^2}}{x}=\frac{(49x^2)^{\frac{1}{2}}}{x}=\frac{49^{\frac{1}{2}}x^{2\cdot\frac{1}{2}}}{x} =7

Therefore the correct answer is answer c.

Answer

7 7

Exercise #3

Solve the following exercise:

x4x= \frac{\sqrt{x^4}}{x}=

Video Solution

Step-by-Step Solution

Express the definition of root as a power:

an=a1n \sqrt[n]{a}=a^{\frac{1}{n}}

Remember that in a square root (also called "root to the power of 2") we don't write the root's power as shown below:

n=2 n=2

Meaning:

a=a2=a12 \sqrt{a}=\sqrt[2]{a}=a^{\frac{1}{2}}

Let's return to the problem and convert the numerator of the fraction by using the root definition that we mentioned above :

x4x=(x4)12x \frac{\sqrt{x^4}}{x}=\frac{(x^4)^{\frac{1}{2}}}{x}

Let's recall the power law for a power of a power:

(am)n=amn (a^m)^n=a^{m\cdot n}

Apply this law to the numerator of the fraction in the expression that we obtained in the last step:

(x4)12x=x412x=x42x \frac{(x^4)^{\frac{1}{2}}}{x}=\frac{x^{4\cdot\frac{1}{2}}}{x}=\frac{x^\frac{4}{2}}{x}

In the first step we applied the above power law and in the second step we performed the multiplication in the power exponent of the numerator term,

Continue to simplify the expression that we obtained. Begin by reducing the fraction with the power exponent in the numerator term and then proceed to apply the power law for division between terms with identical bases:

aman=amn \frac{a^m}{a^n}=a^{m-n}

Simplify the fraction in the now complete expression:

x42x=x2x=x21=x \frac{x^\frac{4}{2}}{x}=\frac{x^2}{x}=x^{2-1}=x

Let's summarize the various steps of the solution that we obtained: As shown below

x4x=(x4)12x=x2x=x \frac{\sqrt{x^4}}{x}=\frac{(x^4)^{\frac{1}{2}}}{x}=\frac{x^2}{x}=x

Therefore the correct answer is answer A.

Answer

x x

Exercise #4

Solve the following exercise:

36x4x2= \frac{\sqrt{36x^4}}{\sqrt{x^2}}=

Video Solution

Step-by-Step Solution

To solve the problem, we will simplify the expression step-by-step:

  • Step 1: Simplify 36x4\sqrt{36x^4}
    We know that 36x4\sqrt{36x^4} can be rewritten as 36x4\sqrt{36} \cdot \sqrt{x^4}.
    First, simplify 36\sqrt{36}:
    36=6\sqrt{36} = 6 because 62=366^2 = 36.
    Next, simplify x4\sqrt{x^4}:
    x4=x2\sqrt{x^4} = x^2 because (x2)2=x4(x^2)^2 = x^4.
  • Step 2: Simplify x2\sqrt{x^2}
    x2=x\sqrt{x^2} = x (assuming x0x \geq 0 to avoid absolute values).
  • Step 3: Simplify the expression 36x4x2\frac{\sqrt{36x^4}}{\sqrt{x^2}}
    Substitute the values obtained in the above steps:
    36x4x2=6x2x\frac{\sqrt{36x^4}}{\sqrt{x^2}} = \frac{6x^2}{x}.
    The expression simplifies to 6x6x as x2x=x\frac{x^2}{x} = x.

Therefore, the solution to the problem is 6x 6x , which matches choice 4.

Answer

6x 6x

Exercise #5

Solve the following exercise:

100x425x2= \sqrt{\frac{100x^4}{25x^2}}=

Video Solution

Step-by-Step Solution

Let's solve the problem by following these steps:

  • Step 1: Simplify the fraction under the square root.
    The expression is 100x425x2\frac{100x^4}{25x^2}. We can simplify this by dealing with the coefficient and the variable separately:
    • The numerical part: 10025=4\frac{100}{25} = 4.
    • The variable part: x4x2=x42=x2\frac{x^4}{x^2} = x^{4-2} = x^2, using the laws of exponents.

    Thus, the simplified fraction is 4x24x^2.

  • Step 2: Apply the square root.
    We have 4x2\sqrt{4x^2}. We apply the square root to both terms:
    • 4=2\sqrt{4} = 2, since 2 squared equals 4.
    • x2=x\sqrt{x^2} = x, assuming xx is positive (or using the absolute value to ensure non-negativity, but the context suggests a straightforward approach).

    Thus, 4x2=2x\sqrt{4x^2} = 2x.

  • Conclusion:
  • Therefore, the solution to the expression is 2x2x.

Answer

2x 2x

Exercise #6

Solve the following exercise:

x8x4= \sqrt{\frac{x^8}{x^4}}=

Video Solution

Step-by-Step Solution

To solve this problem, we'll simplify the given expression step by step.

Firstly, observe the expression: x8x4\sqrt{\frac{x^8}{x^4}}.

  • Step 1: Apply the quotient of powers rule: The expression inside the square root is x8x4\frac{x^8}{x^4}, which simplifies to x84=x4x^{8-4} = x^4 using the rule xmxn=xmn\frac{x^m}{x^n} = x^{m-n}.
  • Step 2: Apply the square root rule: Now we have x4\sqrt{x^4}. Utilizing the property of square roots, we find x4=x4/2=x2\sqrt{x^4} = x^{4/2} = x^2.

Therefore, the simplified expression is x2\textbf{x}^2.

Thus, the final solution to the problem is x2\textbf{x}^2, which corresponds to choice 2 in the given list of options.

Answer

x2 x^2

Exercise #7

Solve the following exercise:

144x816x2= \sqrt{\frac{144x^8}{16x^2}}=

Video Solution

Step-by-Step Solution

To solve this problem, we will follow these steps:

  • Step 1: Simplify the fraction under the square root.
  • Step 2: Apply the square root property to the simplified result.
  • Step 3: Simplify the final expression.

Now, let’s work through each step:

Step 1: Simplify the fraction 144x816x2\frac{144x^8}{16x^2}.

Divide the coefficients: 14416=9\frac{144}{16} = 9.

Subtract the exponents of xx: x82=x6x^{8-2} = x^6.

Thus, the simplified fraction is 9x69x^6.

Step 2: Apply the square root property on 9x69x^6.

The square root of a product is the product of the square roots, so we have:

9x6=9x6\sqrt{9x^6} = \sqrt{9} \cdot \sqrt{x^6}.

Step 3: Simplify the result.

9=3\sqrt{9} = 3.

x6=x62=x3\sqrt{x^6} = x^{\frac{6}{2}} = x^3.

Therefore, the expression simplifies to 3x33x^3.

Thus, the solution to the problem is 3x3 3x^3 .

Answer

3x3 3x^3

Exercise #8

Solve the following exercise:

196x249= \sqrt{\frac{196x^2}{49}}=

Video Solution

Step-by-Step Solution

To solve this problem, we'll apply these steps:

  • Step 1: Simplify the fraction 196x249\frac{196x^2}{49}.
  • Step 2: Apply the square root quotient property.
  • Step 3: Simplify each term to find the final simplified form.

Now, let's perform each step:

Step 1: Simplify the fraction inside the square root:

196x249=19649×x2\frac{196x^2}{49} = \frac{196}{49} \times x^2

Simplify 19649\frac{196}{49}: Since 196÷49=4196 \div 49 = 4, we have 19649=4\frac{196}{49} = 4.

The expression therefore simplifies to 4x24x^2.

Step 2: Apply the square root quotient property:

4x2=4×x2\sqrt{4x^2} = \sqrt{4} \times \sqrt{x^2}

Step 3: Simplify each term:

4=2\sqrt{4} = 2 and x2=x\sqrt{x^2} = x (assuming x0x \geq 0).

Therefore, the expression simplifies to 2x2x.

Thus, the solution to the problem is 2x\boxed{2x}.

Answer

2x 2x

Exercise #9

Solve the following exercise:

25x8225x4= \sqrt{\frac{25x^8}{225x^4}}=

Video Solution

Step-by-Step Solution

Let's solve the problem step by step:

Step 1: Simplify the fraction inside the square root:
25x8225x4 \frac{25x^8}{225x^4}

Divide both the numerator and the denominator by the greatest common factors. Notice that 25 25 and 225 225 have a common factor of 25 25 , and x8 x^8 and x4 x^4 have a common factor of x4 x^4 .

The simplification becomes:
25÷25x84225÷25x44=1x491=x49 \frac{25 \div 25 \cdot x^{8-4}}{225 \div 25 \cdot x^{4-4}} = \frac{1 \cdot x^4}{9 \cdot 1} = \frac{x^4}{9}

Step 2: Apply the Quotient Property of Square Roots:
x49=x49 \sqrt{\frac{x^4}{9}} = \frac{\sqrt{x^4}}{\sqrt{9}}

Step 3: Simplify the square roots:
Since x4=x2 \sqrt{x^4} = x^2 (assuming x0 x \geq 0 as square roots imply non-negative results), and 9=3 \sqrt{9} = 3 ,
x49=x23 \frac{\sqrt{x^4}}{\sqrt{9}} = \frac{x^2}{3}

Therefore, the solution to the problem is 13x2 \frac{1}{3}x^2 .

Answer

13x2 \frac{1}{3}x^2

Exercise #10

Solve the following exercise:

225x49x2= \sqrt{\frac{225x^4}{9x^2}}=

Video Solution

Step-by-Step Solution

To solve this problem, we'll divide this task into clear steps:

  • Step 1: Rewrite the expression using the square root property ab=ab\sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}}. So, 225x49x2=225x49x2\sqrt{\frac{225x^4}{9x^2}} = \frac{\sqrt{225x^4}}{\sqrt{9x^2}}.
  • Step 2: Simplify 225x4\sqrt{225x^4}. This can be broken down as 225×x4\sqrt{225} \times \sqrt{x^4}.
  • Step 3: Simplify each part: 225=15\sqrt{225} = 15 and x4=x2\sqrt{x^4} = x^2 since (x2)2=x4(x^2)^2 = x^4.
  • Step 4: Now, simplify 9x2\sqrt{9x^2}. This is 9×x2\sqrt{9} \times \sqrt{x^2}.
  • Step 5: Simplify these parts: 9=3\sqrt{9} = 3 and x2=x\sqrt{x^2} = x (assuming x>0x > 0 for simplification purposes).
  • Step 6: Putting it all together, 225x49x2=15x23x \frac{\sqrt{225x^4}}{\sqrt{9x^2}} = \frac{15x^2}{3x}.
  • Step 7: Simplify the fraction: 15x23x=5x\frac{15x^2}{3x} = 5x (since x2x=x\frac{x^2}{x} = x).

Therefore, the solution to the problem is 5x 5x .

In the choices provided, the correct answer that matches our solution is choice 2: 5x5x.

Answer

5x 5x

Exercise #11

Solve the following exercise:

144x109x4= \sqrt{\frac{144x^{10}}{9x^4}}=

Video Solution

Step-by-Step Solution

To solve this problem, we will proceed as follows:

  • Step 1: Simplify the expression inside the square root.
  • Step 2: Apply the square root to both the numerator and the denominator separately.
  • Step 3: Simplify the resulting expression.

Let's go through each step:

Step 1: Simplify the fraction 144x109x4\frac{144x^{10}}{9x^4}.

In the given expression 144x109x4\frac{144x^{10}}{9x^4}, separate the numeric part from the variable part:

1449=16\frac{144}{9} = 16 and x10x4=x104=x6\frac{x^{10}}{x^4} = x^{10-4} = x^6.

Thus, the expression simplifies to 16x616x^6.

Step 2: Apply the square root property ab=ab\sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}} to each part.

144x109x4=16x6\sqrt{\frac{144x^{10}}{9x^4}} = \sqrt{16x^6}.

Now separate into numeric and variable components: 16x6\sqrt{16}\cdot\sqrt{x^6}.

16=4\sqrt{16} = 4 because 42=164^2 = 16.

x6=(x6)1/2=x6/2=x3\sqrt{x^6} = (x^6)^{1/2} = x^{6/2} = x^3.

Step 3: Combine the results.

Combine the simplified components: 4x34x^3.

Therefore, the solution to the problem is 4x3 \boxed{4x^3} .

Answer

4x3 4x^3

Exercise #12

Solve the following exercise:

64x2x4= \sqrt{\frac{64x^2}{x^4}}=

Video Solution

Step-by-Step Solution

To solve this problem, we'll simplify the expression inside the square root step-by-step:

  • Step 1: Simplify the fraction 64x2x4\frac{64x^2}{x^4} using the quotient rule for exponents:
    • 64x2x4=64x24=64x2\frac{64x^2}{x^4} = 64 \cdot x^{2-4} = 64 \cdot x^{-2}.
  • Step 2: Now apply the square root to the simplified expression:
    • 64x2x4=64x2=64x2\sqrt{\frac{64x^2}{x^4}} = \sqrt{64x^{-2}} = \sqrt{64} \cdot \sqrt{x^{-2}}.
    • 64=8\sqrt{64} = 8 and x2=x1\sqrt{x^{-2}} = x^{-1} (since it represents inverse squaring).
    • Thus, 64x2=8x1=8x\sqrt{64x^{-2}} = 8 \cdot x^{-1} = \frac{8}{x}.

Therefore, the solution to the problem is 8x \frac{8}{x} , which matches choice 1.

Answer

8x \frac{8}{x}

Exercise #13

Solve the following exercise:

64x416x2= \sqrt{\frac{64x^4}{16x^2}}=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Simplify the expression inside the square root.
  • Step 2: Apply the square root property to the simplified expression.
  • Step 3: Confirm the result with the answer choices.

Now, let's work through each step:

Step 1: Simplify the expression inside the square root:
We have 64x416x2 \frac{64x^4}{16x^2} . Divide the coefficients and the powers of xx:
6416=4 \frac{64}{16} = 4 and using exponents, x4x2=x42=x2 \frac{x^4}{x^2} = x^{4-2} = x^2 .
Therefore, 64x416x2=4x2 \frac{64x^4}{16x^2} = 4x^2 .

Step 2: Apply the square root property:
4x2=4x2=2x=2x \sqrt{4x^2} = \sqrt{4} \cdot \sqrt{x^2} = 2 \cdot x = 2x .

Therefore, the solution to the problem is 2x 2x .

Answer

2x 2x

Exercise #14

Solve the following exercise:

x8x10= \sqrt{\frac{x^8}{x^{10}}}=

Video Solution

Step-by-Step Solution

To solve this mathematical expression, follow these steps:

  • Step 1: Use the Quotient Property of Exponents

    Simplify the expression inside the square root using the rule:
    x8x10=x810=x2 \frac{x^8}{x^{10}} = x^{8-10} = x^{-2} .

  • Step 2: Apply the Square Root Property

    Now, apply the square root:
    x2=(x2)1/2=x212=x1 \sqrt{x^{-2}} = (x^{-2})^{1/2} = x^{-2 \cdot \frac{1}{2}} = x^{-1} .

  • Step 3: Express in Simpler Form

    The expression x1 x^{-1} can be written as 1x\frac{1}{x}.

Therefore, the final simplified form of the expression is 1x \frac{1}{x} .

Answer

1x \frac{1}{x}

Exercise #15

Solve the following exercise:

x20x24= \sqrt{\frac{x^{20}}{x^{24}}}=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Simplify the expression inside the square root using exponent rules.
  • Evaluate the square root of the simplified expression.

Let's work through the solution step-by-step:

First, simplify the expression inside the square root. We have:

x20x24=x2024=x4 \frac{x^{20}}{x^{24}} = x^{20-24} = x^{-4}

Next, apply the square root to the simplified expression:

x4=(x4)1/2=x4×12=x2 \sqrt{x^{-4}} = \left(x^{-4}\right)^{1/2} = x^{-4 \times \frac{1}{2}} = x^{-2}

This can be written as:

x2=1x2 x^{-2} = \frac{1}{x^2}

Therefore, the solution to the problem is 1x2\frac{1}{x^2}.

Answer

1x2 \frac{1}{x^2}