18x−7+4x−9−8x=?
\( 18x-7+4x-9-8x=\text{?} \)
\( 8y+45-34y-45z=\text{?} \)
\( 7.3\cdot4a+2.3+8a=\text{?} \)
\( 3x+4x+7+2=\text{?} \)
\( 3z+19z-4z=\text{?} \)
To solve the exercise, we will reorder the numbers using the substitution property.
To continue, let's remember an important rule:
1. It is impossible to add or subtract numbers with variables.
That is, we cannot subtract 7 from 8X, for example...
We solve according to the order of arithmetic operations, from left to right:
Remember, these two numbers cannot be added or subtracted, so the result is:
To solve this question, we need to remember that we can perform addition and subtraction operations when we have the same variable,
but we are limited when we have several different variables.
We can see in this exercise that we have three variables:
which has no variable
and which both have the variable
and with the variable
Therefore, we can only operate with the y variable, since it's the only one that exists in more than one term.
Let's rearrange the exercise:
Let's combine the relevant terms with
We can see that this is similar to one of the other answers, with a small rearrangement of the terms:
And since we have no possibility to perform additional operations - this is the solution!
It is important to remember that when we have numbers and variables, it is impossible to add or subtract them from each other.
We group the elements:
29.2a + 2.3 + 8a =
And in this exercise, this is the solution!
You can continue looking for the value of a.
But in this case, there is no need.
\( 35m+9n-48m+52n=? \)
\( 5a+3a+8b+10b=\text{?} \)
\( 7a+8b+4a+9b=\text{?} \)
\( 13a+14b+17c-4a-2b-4b=\text{?} \)
\( a+b+bc+9a+10b+3c=\text{?} \)
\( 3.4-3.4a+2.6b-7.5a=\text{?} \)
\( 39.3:4a+5a+8.2+13z=\text{?} \)
\( 5.6x+7.9y+53xy+12.1x=\text{?} \)
\( 7.8+3.5a-80b-7.8b+3.9a=\text{?} \)
\( \frac{1}{4}a+\frac{1}{3}x+\frac{2}{4}a+\frac{1}{8}+\frac{3}{8}=\text{?} \)
\( \frac{3}{8}a+\frac{14}{9}b+1\frac{1}{9}b+\frac{6}{8}a=\text{?} \)