Solve (x+y-z)(2x-y): Multiplying Two Algebraic Expressions

Question

Solve:

(x+yz)(2xy)= (x+y-z)\cdot(2x-y)=

Video Solution

Step-by-Step Solution

To expand and solve the expression (x+yz)(2xy)(x+y-z) \cdot (2x-y), follow these steps:

Step 1: Apply the distributive property to the expression.
We distribute each term in (x+yz)(x+y-z) to each term in (2xy)(2x-y).

Step 2: Calculate the products:
- First, distribute xx to both 2x2x and y-y:

  • x2x=2x2 x \cdot 2x = 2x^2
  • x(y)=xy x \cdot (-y) = -xy

- Next, distribute yy to both 2x2x and y-y:

  • y2x=2xy y \cdot 2x = 2xy
  • y(y)=y2 y \cdot (-y) = -y^2

- Finally, distribute z-z to both 2x2x and y-y:

  • z2x=2xz -z \cdot 2x = -2xz
  • z(y)=yz -z \cdot (-y) = yz

Step 3: Combine all the terms from the above calculations:
2x2xy+2xyy22xz+yz2x^2 - xy + 2xy - y^2 - 2xz + yz.

Step 4: Simplify by combining like terms:
- Combine xy-xy and 2xy2xy to get xyxy.

Therefore, the expanded expression is:
2x2+xyy22xz+yz2x^2 + xy - y^2 - 2xz + yz.

This corresponds to choice 11.

Hence, the correct expanded expression is 2x2+xyy22xz+yz2x^2 + xy - y^2 - 2xz + yz.

Answer

2x2+xyy22xz+yz 2x^2+xy-y^2-2xz+yz