Solve:
(x+y−z)⋅(2x−y)=
To expand and solve the expression (x+y−z)⋅(2x−y), follow these steps:
Step 1: Apply the distributive property to the expression.
We distribute each term in (x+y−z) to each term in (2x−y).
Step 2: Calculate the products:
- First, distribute x to both 2x and −y:
- x⋅2x=2x2
- x⋅(−y)=−xy
- Next, distribute y to both 2x and −y:
- y⋅2x=2xy
- y⋅(−y)=−y2
- Finally, distribute −z to both 2x and −y:
- −z⋅2x=−2xz
- −z⋅(−y)=yz
Step 3: Combine all the terms from the above calculations:
2x2−xy+2xy−y2−2xz+yz.
Step 4: Simplify by combining like terms:
- Combine −xy and 2xy to get xy.
Therefore, the expanded expression is:
2x2+xy−y2−2xz+yz.
This corresponds to choice 1.
Hence, the correct expanded expression is 2x2+xy−y2−2xz+yz.
2x2+xy−y2−2xz+yz