Solve the Nested Radical: Finding √√2

Question

Solve the following exercise:

2= \sqrt{\sqrt{2}}=

Video Solution

Solution Steps

00:00 Solve the following problem
00:03 A 'regular' root is of the order 2
00:09 When we have a number (A) under a root of the order (B) under a root of the order (C)
00:14 The result equals the number (A) under a root of the order of their product (B times C)
00:18 Apply this formula to our exercise
00:23 Calculate the order of multiplication
00:29 This is the solution

Step-by-Step Solution

To solve 2\sqrt{\sqrt{2}}, we will use the property of roots.

  • Step 1: Recognize that 2\sqrt{\sqrt{2}} involves two square roots.
  • Step 2: Each square root can be expressed using exponents: 2=21/2\sqrt{2} = 2^{1/2}.
  • Step 3: Therefore, 2=(21/2)1/2\sqrt{\sqrt{2}} = (2^{1/2})^{1/2}.
  • Step 4: Apply the formula for the root of a root: (xa)b=xab(x^{a})^{b} = x^{ab}.
  • Step 5: For (21/2)1/2(2^{1/2})^{1/2}, this means we compute the product of the exponents: (1/2)×(1/2)=1/4(1/2) \times (1/2) = 1/4.
  • Step 6: The expression simplifies to 21/42^{1/4}, which is written as 24\sqrt[4]{2}.

Therefore, 2=24\sqrt{\sqrt{2}} = \sqrt[4]{2}.

This corresponds to choice 2: 24 \sqrt[4]{2} .

The solution to the problem is 24 \sqrt[4]{2} .

Answer

24 \sqrt[4]{2}