Solve the Linear Equation: Applying Distributive Property in 3(a+1) - 3 = 0

Question

3(a+1)3=0 3(a+1)-3=0

Video Solution

Solution Steps

00:00 Solve
00:03 Open brackets properly, multiply by each factor
00:11 Collect terms
00:23 Isolate A
00:30 And this is the solution to the question

Step-by-Step Solution

Let's proceed to solve the linear equation 3(a+1)3=0 3(a+1) - 3 = 0 :

Step 1: Distribute the 3 in the expression 3(a+1) 3(a+1) .

We get:
3a+313=0 3 \cdot a + 3 \cdot 1 - 3 = 0

This simplifies to:
3a+33=0 3a + 3 - 3 = 0

Step 2: Simplify the expression by combining like terms.

We simplify this to:
3a+0=0 3a + 0 = 0 or simply 3a=0 3a = 0

Step 3: Isolate a a by dividing both sides by 3.

3a3=03\frac{3a}{3} = \frac{0}{3}

Thus,
a=0 a = 0

Therefore, the solution to the problem is a=0 a = 0 .

The correct choice is the option corresponding to a=0 a = 0 .

Answer

a=0 a=0