Solve the Fraction Equation: Finding X in (1/8)(x-3) + 5x = 1

Question

Solve for x:

18(x3)+5x=1 \frac{1}{8}(x-3)+5x=1

Video Solution

Solution Steps

00:00 Find X
00:03 Multiply by the denominator to eliminate the fraction
00:19 Simplify what's possible
00:29 Arrange the equation so that only the unknown X is on one side
00:40 Collect like terms
00:45 Isolate X
00:51 And that's the solution to the problem

Step-by-Step Solution

To solve the given equation, 18(x3)+5x=1\frac{1}{8}(x - 3) + 5x = 1, we will proceed with the following steps:

  • Step 1: Distribute 18\frac{1}{8} across the terms inside the parenthesis.

  • Step 2: Combine like terms to simplify the equation.

  • Step 3: Isolate the variable xx to find its value.

Now, let's work through each step:
Step 1: Distribute 18\frac{1}{8} into the terms inside the parentheses:

18x183=x838 \frac{1}{8} \cdot x - \frac{1}{8} \cdot 3 = \frac{x}{8} - \frac{3}{8}

So the equation becomes:

x838+5x=1 \frac{x}{8} - \frac{3}{8} + 5x = 1

Step 2: Combine like terms. First, combine the terms with xx:

5x+x8=40x8+x8=41x8 5x + \frac{x}{8} = \frac{40x}{8} + \frac{x}{8} = \frac{41x}{8}

Substitute back into the equation:

41x838=1 \frac{41x}{8} - \frac{3}{8} = 1

Step 3: Isolate xx: add 38\frac{3}{8} to both sides:

41x8=1+38 \frac{41x}{8} = 1 + \frac{3}{8} 41x8=88+38=118 \frac{41x}{8} = \frac{8}{8} + \frac{3}{8} = \frac{11}{8}

Multiply both sides by 8 to eliminate the fraction:

41x=11 41x = 11

Finally, divide both sides by 41 to solve for xx:

x=1141 x=\frac{11}{41}

Answer

1141 \frac{11}{41}