Solve the Fraction Equation: -1/2 + (1/3)x = 1/5 + x

Linear Equations with Mixed Fractional Terms

Solve for x:

12+13x=15x -\frac{1}{2}+\frac{1}{3}x=\frac{1}{5}-x

❤️ Continue Your Math Journey!

We have hundreds of course questions with personalized recommendations + Account 100% premium

Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:06 Let's find the value of X.
00:10 First, rearrange the equation so that X is alone on one side.
00:35 Next, combine the like terms together.
00:40 Then, find a common denominator and multiply as needed.
00:55 Now, convert any mixed numbers into fractions.
01:01 To isolate X, multiply by the reciprocal of the fraction.
01:09 Remember, multiply the numerators together and the denominators together.
01:15 And that's how we solve the problem! Great job!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve for x:

12+13x=15x -\frac{1}{2}+\frac{1}{3}x=\frac{1}{5}-x

2

Step-by-step solution

We will move the elements with the X to the left side and the elements without the X to the right side, changing the plus and minus signs accordingly.

First, we move the minus X to the left section:

12+13x+x=15 -\frac{1}{2}+\frac{1}{3}x+x=\frac{1}{5}

Now we move the minus 1/2 to the right section:

13x+x=15+12 \frac{1}{3}x+x=\frac{1}{5}+\frac{1}{2}

We will find a common denominator for the fractions on the right side and reduce accordingly. Convert the mixed fraction on the left side into a simple fraction:

113x=2+510 1\frac{1}{3}x=\frac{2+5}{10}

43x=710 \frac{4}{3}x=\frac{7}{10}

Multiply by34 \frac{3}{4} to reduce the left side:

x=710×34=7×310×4=2140 x=\frac{7}{10}\times\frac{3}{4}=\frac{7\times3}{10\times4}=\frac{21}{40}

3

Final Answer

2140 \frac{21}{40}

Key Points to Remember

Essential concepts to master this topic
  • Rule: Collect like terms by moving variables to one side first
  • Technique: 13x+x=43x \frac{1}{3}x + x = \frac{4}{3}x when combining fractional coefficients
  • Check: Substitute 2140 \frac{21}{40} : both sides equal 18 \frac{1}{8}

Common Mistakes

Avoid these frequent errors
  • Adding fractions with different denominators incorrectly
    Don't add 15+12=27 \frac{1}{5} + \frac{1}{2} = \frac{2}{7} ! This gives completely wrong results because you can't add numerators and denominators separately. Always find the LCD first: 15+12=210+510=710 \frac{1}{5} + \frac{1}{2} = \frac{2}{10} + \frac{5}{10} = \frac{7}{10} .

Practice Quiz

Test your knowledge with interactive questions

\( x+x=8 \)

FAQ

Everything you need to know about this question

How do I combine 13x+x \frac{1}{3}x + x when one term doesn't show a fraction?

+

Remember that x is the same as 11x \frac{1}{1}x ! To add them, convert to the same denominator: 13x+33x=43x \frac{1}{3}x + \frac{3}{3}x = \frac{4}{3}x .

Why do I need to find a common denominator for 15+12 \frac{1}{5} + \frac{1}{2} ?

+

You cannot add fractions until they have the same bottom number (denominator). The LCD of 5 and 2 is 10, so: 15=210 \frac{1}{5} = \frac{2}{10} and 12=510 \frac{1}{2} = \frac{5}{10} .

How do I multiply 710×34 \frac{7}{10} \times \frac{3}{4} correctly?

+

Multiply straight across: numerator × numerator and denominator × denominator. So 7×310×4=2140 \frac{7 \times 3}{10 \times 4} = \frac{21}{40} . No common denominator needed for multiplication!

What if I get confused about which side to move terms to?

+

A good strategy is to move all x terms to the left and all numbers to the right. This keeps your work organized and reduces mistakes!

How can I check if 2140 \frac{21}{40} is really the right answer?

+

Substitute back into the original equation: 12+132140=152140 -\frac{1}{2} + \frac{1}{3} \cdot \frac{21}{40} = \frac{1}{5} - \frac{21}{40} . Both sides should equal 18 -\frac{1}{8} when calculated correctly.

🌟 Unlock Your Math Potential

Get unlimited access to all 18 Linear Equations (One Variable) questions, detailed video solutions, and personalized progress tracking.

📹

Unlimited Video Solutions

Step-by-step explanations for every problem

📊

Progress Analytics

Track your mastery across all topics

🚫

Ad-Free Learning

Focus on math without distractions

No credit card required • Cancel anytime

More Questions

Click on any question to see the complete solution with step-by-step explanations