Solve Fourth and Sixth Roots: Multiplying √⁴3 × √⁶3

Question

Solve the following exercise:

3436= \sqrt[4]{3}\cdot\sqrt[6]{3}=

Video Solution

Solution Steps

00:00 Simplify the equation
00:03 The C root of number A to the power of B
00:06 The result will be equal to the number to the power of B divided by C
00:10 Every number is essentially to the power of 1
00:13 We will use this formula in our exercise
00:16 When multiplying powers with equal bases
00:20 The power of the result equals the sum of the powers
00:23 We will use this formula in our exercise and add the powers
00:27 And this is the solution to the question

Step-by-Step Solution

In order to simplify the given expression we use two laws of exponents:

A. Defining the root as an exponent:

an=a1n \sqrt[n]{a}=a^{\frac{1}{n}}

B. The law of exponents for multiplication between factors with the same bases:

aman=am+n a^m\cdot a^n=a^{m+n}

Let's start with converting the roots to exponents using the law of exponents shown in A:

3436=314316= \sqrt[\textcolor{red}{4}]{3}\cdot\sqrt[\textcolor{blue}{6}]{3}= \\ \downarrow\\ 3^{\frac{1}{\textcolor{red}{4}}}\cdot3^{\frac{1}{\textcolor{blue}{6}}}=

We continue, since multiplication is performed between two factors with the same bases - we use the law of exponents shown in B:

314316=314+16 3^{\frac{1}{4}}\cdot3^{\frac{1}{6}}= \\ \boxed{3^{\frac{1}{4}+\frac{1}{6}}}

Therefore, the correct answer is answer D.

Answer

314+16 3^{\frac{1}{4}+\frac{1}{6}}