Solve Square Root Multiplication: √7 × √7 Simplification

Question

Solve the following exercise:

77= \sqrt{7}\cdot\sqrt{7}=

Video Solution

Solution Steps

00:00 Solve
00:07 Taking a root is like raising to the inverse power
00:12 Let's use this formula in our exercise
00:16 A 'regular' root is actually a root of 2
00:22 Therefore we'll convert each number to its inverse power (half)
00:27 When multiplying powers with equal bases
00:30 The power of the result equals the sum of the powers
00:35 We'll use this formula in our exercise and add the powers
00:41 And this is the solution to the question

Step-by-Step Solution

In order to simplify the given expression, we will use two laws of exponents:

a. The definition of root as an exponent:

an=a1n \sqrt[n]{a}=a^{\frac{1}{n}} b. The law of exponents for power of a power:

(am)n=amn (a^m)^n=a^{m\cdot n}

Let's start by converting the square roots to exponents using the law mentioned in a':

77=712712= \sqrt{7}\cdot\sqrt{7}= \\ \downarrow\\ 7^{\frac{1}{2}}\cdot7^{\frac{1}{2}}= Let's continue, notice that we got a number multiplied by itself, therefore, according to the definition of exponents we can write the expression we got as a power of that same number, then - we'll use the law of exponents mentioned in b' and perform the exponentiation on the term in parentheses:

712712=(712)2=7122=71=7 7^{\frac{1}{2}}\cdot7^{\frac{1}{2}}= \\ (7^{\frac{1}{2}})^2=\\ 7^{\frac{1}{2}\cdot2}=\\ 7^1=\\ \boxed{7} Therefore, the correct answer is answer a'.

Answer

7 7