Solve for X: Finding X in ½(8-x) + ½x = 12-x Linear Equation

Solve for X:

12(8x)+12x=12x \frac{1}{2}\cdot(8-x)+\frac{1}{2}x=12-x

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:10 Let's solve this together!
00:14 First, we want to isolate the unknown variable X.
00:18 Make sure to open the parentheses correctly, and multiply each term inside.
00:34 Next, divide 8 by 2.
00:37 Remember, a positive times a negative gives a negative.
00:48 Now, let's simplify whatever we can.
00:54 Our goal is to isolate the unknown, X.
01:10 Again, let's simplify the expression.
01:20 Multiply by negative 1 to change a negative to a positive.
01:30 And remember, negative times negative gives us a positive.
01:35 And there you have it! That's the solution to our problem.

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve for X:

12(8x)+12x=12x \frac{1}{2}\cdot(8-x)+\frac{1}{2}x=12-x

2

Step-by-step solution

To solve the equation 12(8x)+12x=12x \frac{1}{2} \cdot (8-x) + \frac{1}{2}x = 12 - x , follow these steps:

  • Step 1: Use the distributive property on the left side of the equation.
    • Distribute 12 \frac{1}{2} across (8x) (8-x) :
    • This gives us 12812x+12x \frac{1}{2} \cdot 8 - \frac{1}{2} \cdot x + \frac{1}{2}x .
    • Simplify the terms: 412x+12x 4 - \frac{1}{2}x + \frac{1}{2}x .
  • Step 2: Simplify the left side of the equation:
    • The terms 12x -\frac{1}{2}x and 12x \frac{1}{2}x cancel each other out.
    • Thus, the left side simplifies to 4 4 .
  • Step 3: Set the simplified equation equal to the right side:
    • So, we have 4=12x 4 = 12 - x .
  • Step 4: Solve for x x using basic algebra:
    • Add x x to both sides to move x x to one side: x+4=12 x + 4 = 12 .
    • Subtract 4 from both sides to solve for x x : x=124 x = 12 - 4 .
    • This results in x=8 x = 8 .

Therefore, the solution to the equation is x=8 x = 8 .

3

Final Answer

8 8

Practice Quiz

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\( x+7=14 \)

\( x=\text{?} \)

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