Solve for X: Finding the Value in (2/4 + 1/2 + 3/8 - 1/5)x = 1

Question

Solve for X:

24x+12x+38x15x=1 \frac{2}{4}x+\frac{1}{2}x+\frac{3}{8}x-\frac{1}{5}x=1

Video Solution

Solution Steps

00:00 Solve
00:04 We want to isolate the unknown X
00:10 Multiply by the common denominator to eliminate fractions
00:20 Divide 40 by each appropriate fraction
00:31 Solve each multiplication separately
00:51 Collect terms
01:05 Isolate the unknown X
01:17 And this is the solution to the question

Step-by-Step Solution

To solve this equation, we will follow these steps:

  • Step 1: Identify the least common denominator (LCD) for the fractions 24x \frac{2}{4}x , 12x \frac{1}{2}x , 38x \frac{3}{8}x , and 15x \frac{1}{5}x .
  • Step 2: Convert each fraction to have the LCD as the denominator.
  • Step 3: Combine the fractions to form a single expression.
  • Step 4: Solve the resulting equation for x x .

Now, let's work through each step:

Step 1: The denominators are 4, 2, 8, and 5. The LCD of these numbers is 40.

Step 2: Convert each fraction:

24x=2×1040x=2040x \frac{2}{4}x = \frac{2 \times 10}{40}x = \frac{20}{40}x

12x=1×2040x=2040x \frac{1}{2}x = \frac{1 \times 20}{40}x = \frac{20}{40}x

38x=3×540x=1540x \frac{3}{8}x = \frac{3 \times 5}{40}x = \frac{15}{40}x

15x=1×840x=840x -\frac{1}{5}x = -\frac{1 \times 8}{40}x = -\frac{8}{40}x

Step 3: Combine all fractions:

2040x+2040x+1540x840x \frac{20}{40}x + \frac{20}{40}x + \frac{15}{40}x - \frac{8}{40}x

=20+20+15840x = \frac{20 + 20 + 15 - 8}{40}x

=4740x = \frac{47}{40}x

Step 4: Solve the equation 4740x=1 \frac{47}{40}x = 1 .

Multiply both sides by 4047 \frac{40}{47} to solve for x x :

x=1×4047 x = 1 \times \frac{40}{47}

x=4047 x = \frac{40}{47}

Therefore, the solution to the problem is x=4047 x = \frac{40}{47} .

Answer

4047 \frac{40}{47}