Solve for X: 1/8x - 2/3x + 1/5x = 1 Linear Equation

Solve for X:

18x23x+15x=1 \frac{1}{8}x-\frac{2}{3}x+\frac{1}{5}x=1

❤️ Continue Your Math Journey!

We have hundreds of course questions with personalized recommendations + Account 100% premium

Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve
00:04 We want to isolate the unknown X
00:08 We'll multiply by the common denominator to eliminate fractions
00:15 We'll divide 120 by each appropriate fraction
00:36 We'll solve each multiplication separately
00:50 We'll group the factors
01:01 We'll isolate the unknown X
01:15 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve for X:

18x23x+15x=1 \frac{1}{8}x-\frac{2}{3}x+\frac{1}{5}x=1

2

Step-by-step solution

The common denominator of 8, 3, and 5 is 120.

Now we multiply each numerator by the corresponding number to reach 120 and thus cancel the fractions and obtain the following equation:

(1×x×15)(2×x×40)+(1×x×24)=1×120 (1\times x\times15)-(2\times x\times40)+(1\times x\times24)=1\times120

We multiply the exercises in parentheses accordingly:

15x80x+24x=120 15x-80x+24x=120

We will solve the left side (from left to right) and will obtain:

(15x80x)+24x=120 (15x-80x)+24x=120

65x+24x=120 -65x+24x=120

41x=120 -41x=120

We reduce both sides by 41 -41

41x41=12041 \frac{-41x}{-41}=\frac{120}{-41}

We find that x is equalx=12041 x=-\frac{120}{41}

3

Final Answer

12041 -\frac{120}{41}

Practice Quiz

Test your knowledge with interactive questions

\( x+7=14 \)

\( x=\text{?} \)

🌟 Unlock Your Math Potential

Get unlimited access to all 18 Linear Equations (One Variable) questions, detailed video solutions, and personalized progress tracking.

📹

Unlimited Video Solutions

Step-by-step explanations for every problem

📊

Progress Analytics

Track your mastery across all topics

🚫

Ad-Free Learning

Focus on math without distractions

No credit card required • Cancel anytime

More Questions

Click on any question to see the complete solution with step-by-step explanations