Solve for b: 4(b/2 + b) - 1/3 = 6b Linear Equation

$4(\frac{b}{2}+b)-\frac{1}{3}=6b$

$b=\text{?}$

First, we'll expand the parentheses by multiplying each term by 4:

$4\times\frac{b}{2}+4\times b-\frac{1}{3}=6b$

Let's then solve the multiplication exercise $4\times\frac{b}{2}=\frac{4b}{2}=2b$.

Now the equation is:

$2b+4b-\frac{1}{3}=6b$

We can now combine the left-hand side between the two $b$ terms to get:

$6b-\frac{1}{3}=6b$

We'll reduce both sides by $6b$, leaving us with:

$-\frac{1}{3}=0$

Since the result obtained is impossible, the exercise has no solution.