Insert the corresponding expression:
(4×53×2)−2= \left(\frac{4\times5}{3\times2}\right)^{-2}= (3×24×5)−2=
4−2×5−23−2×2−2 \frac{4^{-2}\times5^{-2}}{3^{-2}\times2^{-2}} 3−2×2−24−2×5−2