Solve 38÷(-4)×12÷(-3): Sequential Operations with Negative Numbers

Solve the following equation:

$38:(-4)\cdot12:(-3)=$

Let's begin by writing the two division exercises as a multiplication of two simple fractions:

$(38:(-4))\times(12:(-3))=$

$\frac{38}{-4}\times\frac{12}{-3}=$

Let's proceed to combine them into one exercise:

$\frac{38\times12}{-4\times-3}=$

Note that in the denominator of the fraction we are multiplying two negative numbers, therefore the result must be positive:

$\frac{38\times12}{4\times3}=$

Let's now break down the 12 in the fraction's numerator into a multiplication exercise:

$\frac{38\times4\times3}{4\times3}=$

Finally let's reduce the multiplication exercise 4X3 in the numerator and denominator and we should obtain the following:

$38$