Solve -30-(-10): Working with Double Negatives in Subtraction

Question

$-30-(-10)=$

00:00 Solve

00:03 Negative times negative always equals positive

00:07 Open parentheses

00:10 Find the point (-30) on the axis

00:14 The number is directed, positive

00:17 Movement towards the positive side of the axis is to the right

00:21 Let's take 10 jumps to the right

00:35 And this is the solution to the question

Let's remember the following rule:

$-(-x)=+$

Now let's write the exercise in the appropriate form:

$-30+(10)=$

We'll locate the number negative 30 on the number line.

We'll move 10 steps to the right (since 10 is greater than zero):

We can see that we've arrived at the number negative 20.

$-20$