Solve (-(-2)²)² - 2³: Multiple Exponents and Negative Numbers

((2)2)223= (-(-2)^2)^2-2^3=

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Step-by-step video solution

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00:00 Solve
00:03 First let's calculate the sign
00:06 Even power, therefore the sign will be positive
00:13 Let's calculate the powers
00:31 Even power, therefore the sign will be positive
00:38 Let's calculate the square, and continue calculating
00:42 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

((2)2)223= (-(-2)^2)^2-2^3=

2

Step-by-step solution

To solve this problem, we need to carefully apply the order of operations, commonly known as PEMDAS (Parentheses, Exponents, Multiplication and Division, Addition and Subtraction).
Let's evaluate the expression step-by-step:

  • Step 1: Begin with the expression inside the innermost parentheses: (2)2(-2)^2. This means we first square 2-2, which results in 44 because (2)×(2)=4(-2) \times (-2) = 4.
  • Step 2: Now, consider the negative sign outside the squared term. So, evaluate (2)2-(-2)^2, which simplifies to 4-4.
  • Step 3: Next, we need to square 4-4: (4)2=(4)×(4)=16(-4)^2 = (-4) \times (-4) = 16.
  • Step 4: Now, calculate the second part of the expression, 232^3, which equals 88 because 2×2×2=82 \times 2 \times 2 = 8.
  • Step 5: Finally, subtract the result from Step 4 from the result of Step 3: 168=816 - 8 = 8.

Thus, the solution to the problem is 8 8 .

3

Final Answer

8 8

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\( (-2)^7= \)

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