Solve (20-3×2²)²: Order of Operations and Squaring Practice

We begin by solving the expression inside the parentheses $(20-3\times2^2)^2$. According to the order of operations (PEMDAS/BODMAS), we first handle any calculations inside parentheses and deal with exponents before performing multiplication, division, addition, or subtraction.

• Step 1: Solve the exponent inside the parentheses.

We have $2^2$, which equals $4$. Thus, the expression now is:



$(20-3\times4)^2$



• Step 2: Perform the multiplication inside the parentheses.

Multiply $3$ by $4$ to get $12$. The expression now simplifies to:



$(20-12)^2$



• Step 3: Perform the subtraction inside the parentheses.

Subtract $12$ from $20$. We get $8$. The expression now simplifies to:



$(8)^2$



• Step 4: Finally, solve the remaining exponent.

$8^2$ equals $64$.



Thus, $(20-3\times2^2)^2$ equals $64$.