Solve the following problem:
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Solve the following problem:
Upon observing the exercise note that we have two "regular" numbers and one number with a variable. 
Given that this is a multiplication exercise, multiplying a number with a variable by a number without a variable doesn't present a problem.
In fact, it's important to remember that a variable attached to a number represents multiplication itself, for example in this case: 
Therefore, we can apply the distributive property to separate the variable, and come back to it later.
Proceed to solve the exercise from right to left since it's simpler this way.
We obtain the following:
We'll put aside the x and add it at the end of the exercise.
By solving the exercise in an organized way we simplify the solution process.
It's important to maintain the correct order when solving the problem, meaning first multiply the ones of the first number by the ones of the second number,
then the tens of the first number by the ones of the second number, and so on.
Don't forget to add the variable at the end. The answer is as follows:
\( 94+12+6= \)
The variable x represents an unknown number, and we're only multiplying the coefficient (the number in front of x). Think of 11x as "11 groups of x" - when you multiply by 5 and 6, you get "330 groups of x" or 330x.
No! Multiplication is commutative, meaning you can multiply in any order. You could do 5 × 6 = 30 first, then 11 × 30 = 330, or multiply all three: 11 × 5 × 6 = 330.
Multiply the numbers together and keep all variables: 3x × 4y = . Each different variable stays separate in your final answer.
Look at the operation symbol! If you see × (times) or numbers/variables written next to each other like 11x, then multiply. If you see + or -, then add or subtract like terms.
Yes! Pick any number for x and substitute it into both the original problem and your answer. For example: if x = 2, then and ✓
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