Simplify the Square Root Expression: √(12x⁴)

Radical Simplification with Perfect Power Factors

Solve the following exercise:

12x4= \sqrt{12x^4}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Simplify the following expression
00:03 The square root of a number (A) multiplied by the square root of another number (B)
00:07 Equals the square root of their product (A times B)
00:10 Apply this formula to our exercise, and convert from root 1 to two
00:19 Break down X to the fourth into X squared squared
00:26 The square root of any number (A) squared cancels out the square
00:29 Apply this formula to our exercise
00:33 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following exercise:

12x4= \sqrt{12x^4}=

2

Step-by-step solution

In order to simplify the given expression, we will apply the following three laws of exponents:

a. Definition of root as an exponent:

an=a1n \sqrt[n]{a}=a^{\frac{1}{n}}

b. Law of exponents for an exponent applied to terms in parentheses:

(ab)n=anbn (a\cdot b)^n=a^n\cdot b^n

c. Law of exponents for an exponent raised to an exponent:

(am)n=amn (a^m)^n=a^{m\cdot n}

Begin by converting the fourth root to an exponent using the law of exponents mentioned in a.:

12x4=(12x4)12= \sqrt{12x^4}= \\ \downarrow\\ (12x^4)^{\frac{1}{2}}=

Next, apply the law of exponents mentioned in b. and proceed to apply the exponent to each factor inside of the parentheses:

(12x4)12=1212(x4)12 (12x^4)^{\frac{1}{2}}= \\ 12^{\frac{1}{2}}\cdot(x^4)^{{\frac{1}{2}}}

Let's continue, using the law of exponents mentioned in c. and perform the exponent operation on the term with an exponent in the parentheses (the second term in the product):

1212(x4)12=1212x412=1212x2=12x2= 12^{\frac{1}{2}}\cdot(x^4)^{{\frac{1}{2}}} = \\ 12^{\frac{1}{2}}\cdot x^{4\cdot\frac{1}{2}}=\\ 12^{\frac{1}{2}}\cdot x^{2}=\\ \boxed{\sqrt{12} x^2}=\\ In the final step, we converted the one-half exponent on the first term in the product back to a fourth root form, again, according to the definition of root as an exponent mentioned in a. (in the reverse direction).

Therefore, the correct answer is answer c.

3

Final Answer

12x2 \sqrt{12}x^2

Key Points to Remember

Essential concepts to master this topic
  • Rule: Split radicals using ab=ab \sqrt{ab} = \sqrt{a} \cdot \sqrt{b}
  • Technique: Factor out perfect squares: x4=(x2)2 x^4 = (x^2)^2 becomes x2 x^2
  • Check: Verify by squaring: (12x2)2=12x4 (\sqrt{12} \cdot x^2)^2 = 12x^4

Common Mistakes

Avoid these frequent errors
  • Bringing everything outside the radical
    Don't write 12x4=12x2 \sqrt{12x^4} = 12x^2 by moving all factors outside! This gives 144x⁴ when squared, not 12x⁴. Always check which factors are perfect squares - only x4 x^4 is a perfect square here, so only x2 x^2 comes out.

Practice Quiz

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FAQ

Everything you need to know about this question

Why doesn't the 12 come out of the square root?

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Because 12 is not a perfect square! Perfect squares like 4, 9, 16, 25 can come out completely. Since 12=4×3 12 = 4 \times 3 , only the 4 could come out as 2, giving us 23 2\sqrt{3} , but we keep it as 12 \sqrt{12} for simplicity.

How do I know when an exponent can come out of a square root?

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The exponent must be even to come out completely! With square roots, divide the exponent by 2. So x4 x^4 becomes x2 x^2 , but x3 x^3 would stay as xx x \sqrt{x} .

Can I simplify 12 \sqrt{12} further?

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Yes! 12=4×3=43=23 \sqrt{12} = \sqrt{4 \times 3} = \sqrt{4} \cdot \sqrt{3} = 2\sqrt{3} . So the complete answer could be 23x2 2\sqrt{3} \cdot x^2 , but 12x2 \sqrt{12} \cdot x^2 is also correct.

What if the variable had an odd exponent like x5 x^5 ?

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Split it up! x5=x4x=x4x=x2x \sqrt{x^5} = \sqrt{x^4 \cdot x} = \sqrt{x^4} \cdot \sqrt{x} = x^2\sqrt{x} . Take out the largest even power and leave the rest inside.

How can I check my answer is right?

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Square your answer and see if you get the original expression! (12x2)2=12(x2)2=12x4 (\sqrt{12} \cdot x^2)^2 = 12 \cdot (x^2)^2 = 12x^4

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