Simplify the Nested Square Root: √(√(3x²))

Nested Radicals with Exponent Rules

Complete the following exercise:

3x2= \sqrt{\sqrt{3x^2}}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve the following problem
00:03 A "regular" root is of the order 2
00:11 When we have a number (A) to the power of (B) in a root of order (C)
00:14 The result equals the number (A) to the power of their quotient (B times C)
00:18 We will apply this formula to our exercise
00:24 Calculate the order multiplication
00:31 When we have a root of a product (A times B)
00:36 We can write it as the product of the root of each term
00:40 We will apply this formula to our exercise, and proceed to break down the root
00:49 When we have a number (A) to the power of (B) in a root of order (C)
00:52 The result equals the number (A) to the power of their quotient (B divided by C)
00:56 We will apply this formula to our exercise
01:04 Calculate the power quotient
01:12 We'll apply this formula again in the opposite direction, converting from a power to a root
01:22 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Complete the following exercise:

3x2= \sqrt{\sqrt{3x^2}}=

2

Step-by-step solution

To solve 3x2\sqrt{\sqrt{3x^2}}, follow these steps:

  • Step 1: Express the problem using exponentiation. The expression 3x2\sqrt{3x^2} can be written as (3x2)12(3x^2)^{\frac{1}{2}}.
  • Step 2: Take the square root of the first expression. This can be expressed as ((3x2)12)12((3x^2)^{\frac{1}{2}})^{\frac{1}{2}}.
  • Step 3: Use the property (am)n=amn(a^m)^n = a^{m \cdot n}. Thus, ((3x2)12)12=(3x2)14((3x^2)^{\frac{1}{2}})^{\frac{1}{2}} = (3x^2)^{\frac{1}{4}}.
  • Step 4: Simplify further using exponent rules: (3x2)14(3x^2)^{\frac{1}{4}} becomes (314(x2)14)(3^{\frac{1}{4}} \cdot (x^2)^{\frac{1}{4}}), which simplifies to 34x12\sqrt[4]{3} \cdot x^{\frac{1}{2}}.
  • Step 5: Recognize this as 34x\sqrt[4]{3} \cdot \sqrt{x}, since x12x^{\frac{1}{2}} is x\sqrt{x}.

Therefore, the simplified form of the given expression is 34x \sqrt[4]{3} \cdot \sqrt{x} .

3

Final Answer

34x \sqrt[4]{3}\cdot\sqrt{x}

Key Points to Remember

Essential concepts to master this topic
  • Power Rule: Convert nested square roots to fractional exponents first
  • Technique: Apply (am)n=amn(a^m)^n = a^{mn} so (3x2)1/2(3x^2)^{1/2}^{1/2} = (3x^2)^{1/4}\)
  • Check: Verify by converting back to radical form: (3x2)1/4=3x24(3x^2)^{1/4} = \sqrt[4]{3x^2}

Common Mistakes

Avoid these frequent errors
  • Simplifying inner radical before applying outer radical
    Don't simplify 3x2\sqrt{3x^2} to x3x\sqrt{3} first = wrong path! This ignores the absolute value requirement and leads to incorrect final answers. Always convert to fractional exponents and use the power rule (am)n=amn(a^m)^n = a^{mn} directly.

Practice Quiz

Test your knowledge with interactive questions

Solve the following exercise:

\( \sqrt[10]{\sqrt[10]{1}}= \)

FAQ

Everything you need to know about this question

Why can't I just simplify the inner square root first?

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When dealing with nested radicals, it's easier to work with exponents! Converting 3x2\sqrt{\sqrt{3x^2}} to ((3x2)1/2)1/2((3x^2)^{1/2})^{1/2} lets you use the power rule directly.

What's the difference between 34x\sqrt[4]{3}\cdot\sqrt{x} and x34x\sqrt[4]{3}?

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The key difference is in the exponent of x! In 34x\sqrt[4]{3}\cdot\sqrt{x}, we have x1/2x^{1/2}, but in x34x\sqrt[4]{3} we have x1x^1. From (x2)1/4=x21/4=x1/2(x^2)^{1/4} = x^{2 \cdot 1/4} = x^{1/2}, the first form is correct.

How do I know when to use fractional exponents versus radicals?

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Fractional exponents are usually easier for complex operations like nested radicals. Use them when applying exponent rules, then convert back to radical form for the final answer if needed.

Why does (x2)1/4(x^2)^{1/4} equal x1/2x^{1/2} and not just xx?

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Remember the power rule: (am)n=amn(a^m)^n = a^{mn}. So (x2)1/4=x2×1/4=x1/2(x^2)^{1/4} = x^{2 \times 1/4} = x^{1/2}. We multiply the exponents, not add them!

Can I check my answer by substituting a value?

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Yes! Try x=4x = 4: 316=482.63\sqrt{\sqrt{3 \cdot 16}} = \sqrt{\sqrt{48}} ≈ 2.63, and 344=1.316×22.63\sqrt[4]{3}\cdot\sqrt{4} = 1.316 \times 2 ≈ 2.63

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