Simplify the Nested Radical: 10th Root of Square Root of x^20

Question

Comlete the following exercise:

x2010= \sqrt[10]{\sqrt{x^{20}}}=

Video Solution

Solution Steps

00:00 Solve the following problem
00:03 A "regular" root is of the order 2
00:11 When we have a number (A) raised to the power (B) in a root of order (C)
00:17 The result equals the number (A) in a root of order of their product (B times C)
00:21 We will apply this formula to our exercise
00:25 Calculate the multiplication of orders
00:34 When we have a number (A) raised to the power (B) in a root of order (C)
00:40 The result equals the number (A) raised to the power of their quotient (B divided by C)
00:43 We will apply this formula to our exercise
00:49 Calculate the quotient of the powers
00:52 This is the solution

Step-by-Step Solution

To solve the problem, we'll simplify x2010 \sqrt[10]{\sqrt{x^{20}}} using properties of exponents and roots:

  • Step 1: Convert each part into exponent form. We have x20 \sqrt{x^{20}} , which can be rewritten as (x20)1/2(x^{20})^{1/2}.
  • Step 2: Simplify the expression (x20)1/2(x^{20})^{1/2}. Using the power of a power property, this becomes x20(1/2)=x10x^{20 \cdot (1/2)} = x^{10}.
  • Step 3: Apply the 10th root to the simplified result: x1010\sqrt[10]{x^{10}}, which can be written as (x10)1/10(x^{10})^{1/10}.
  • Step 4: Simplify (x10)1/10(x^{10})^{1/10} using the power of a power property again, we get x(10(1/10))=x1=xx^{(10 \cdot (1/10))} = x^1 = x.

Therefore, the expression simplifies to x x .

Conclusion: The solution to the problem is x x .

Answer

x x