Simplify the Expression: Cube Root of √25 × Cube Root of √64

Question

Complete the following exercise:

253643= \sqrt[3]{\sqrt{25}}\cdot\sqrt[3]{\sqrt{64}}=

Video Solution

Solution Steps

00:00 Solve the following problem
00:05 A 'regular' root is of the order 2
00:08 Breakdown 25 to 5 squared
00:13 Breakdown 64 to 8 squared
00:17 The root of any number (A) squared cancels out the square
00:26 Apply this formula to our exercise and proceed to cancel out the squares
00:42 Breakdown 8 to 2 to the power of 3
00:50 A cube root cancels out a power of three
00:53 This is the solution

Step-by-Step Solution

To solve the problem 253643 \sqrt[3]{\sqrt{25}} \cdot \sqrt[3]{\sqrt{64}} , we will work through it step by step:

Step 1: Simplify the inner square roots.

  • 25\sqrt{25} simplifies to 55 because 5×5=255 \times 5 = 25.
  • 64\sqrt{64} simplifies to 88 because 8×8=648 \times 8 = 64.

Step 2: Evaluate the cube roots.

  • 53\sqrt[3]{5} remains as 51/35^{1/3}.
  • 83\sqrt[3]{8} evaluates to 22 because 2×2×2=82 \times 2 \times 2 = 8.

Step 3: Multiply the results of the cube roots.

  • 51/32=2535^{1/3} \cdot 2 = 2 \sqrt[3]{5}.

Thus, the simplified expression is 2532 \sqrt[3]{5}.

Therefore, the solution to the problem is 253 2\sqrt[3]{5} .

Answer

253 2\sqrt[3]{5}