In similar triangles, the area of the triangles is 361 cm² and 81 cm². If it is known that the perimeter of the first triangle is 38, what is the perimeter of the second triangle?
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In similar triangles, the area of the triangles is 361 cm² and 81 cm². If it is known that the perimeter of the first triangle is 38, what is the perimeter of the second triangle?
To begin with we can determine the perimeter of the second triangle by using the equation below.
We insert the existing data
Lastly we multiply by 38 to obtain the following answer:
18
If it is known that both triangles are equilateral, are they therefore similar?
Because area scales with the square of linear dimensions! If one triangle has sides twice as long, its area is four times larger (2²=4), but its perimeter is only twice as large.
It doesn't matter! The formula works both ways. Just be consistent - if S₂ is in the numerator, then P₂ should be too.
That's fine! But check if the numbers under the square root are perfect squares first. Here, and , so we get the clean fraction .
Yes! This square root relationship works for any similar shapes - triangles, rectangles, circles, etc. The key is that the figures must be similar (same shape, different size).
The smaller area (81) should go with the smaller perimeter (18), and the larger area (361) with the larger perimeter (38). Also verify: ✓
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