Match Equivalent Expressions: (a±b)(c±4) Expansions

Binomial Expansion with Sign Patterns

Join expressions of equal value

  1. (ab)(c4) (a-b)(c-4)

  2. (a+b)(c+4) (a+b)(c+4)

  3. (ab)(c+4) (a-b)(c+4)

  4. (a+b)(c4) (a+b)(c-4)

    a.ac4a+bc4b ac-4a+bc-4b

    b.ac+4abc4b ac+4a-bc-4b

    c.ac4abc+4b ac-4a-bc+4b

    d.ac+4a+bc+4b ac+4a+bc+4b

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Open brackets
00:03 Open brackets properly, multiply each factor by each factor
00:14 Calculate the multiplications, and group the factors
00:21 This is the simplification for 1, let's continue to 2
00:27 Open brackets properly, multiply each factor by each factor
00:32 Calculate the multiplications, and group the factors
00:38 This is the simplification for 2, let's continue to 3
00:42 Open brackets properly, multiply each factor by each factor
00:50 Calculate the multiplications, and group the factors
00:53 This is the simplification for 3, let's continue to 4
01:00 Open brackets properly, multiply each factor by each factor
01:03 Calculate the multiplications, and group the factors
01:10 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Join expressions of equal value

  1. (ab)(c4) (a-b)(c-4)

  2. (a+b)(c+4) (a+b)(c+4)

  3. (ab)(c+4) (a-b)(c+4)

  4. (a+b)(c4) (a+b)(c-4)

    a.ac4a+bc4b ac-4a+bc-4b

    b.ac+4abc4b ac+4a-bc-4b

    c.ac4abc+4b ac-4a-bc+4b

    d.ac+4a+bc+4b ac+4a+bc+4b

2

Step-by-step solution

We use all the exercises of the extended distributive property:(a+b)×(c+d)=ac+ad+bc+bd (a+b)\times(c+d)=ac+ad+bc+bd

1.(ab)(c4)=ac4abc+4b (a-b)(c-4)=ac-4a-bc+4b

2.(a+b)(c+4)=ac+4a+bc+4b (a+b)(c+4)=ac+4a+bc+4b

3.(ab)(c+4)=ac+4abc4b (a-b)(c+4)=ac+4a-bc-4b

4.(a+b)(c4)=ac4a+bc4b (a+b)(c-4)=ac-4a+bc-4b

3

Final Answer

1-c, 2-d, 3-b, 4-a

Key Points to Remember

Essential concepts to master this topic
  • FOIL Method: First, Outer, Inner, Last terms multiply systematically
  • Sign Rules: (ab)(c+4)=ac+4abc4b (a-b)(c+4) = ac + 4a - bc - 4b follows pattern
  • Verification: Check each term matches: ac term, constant multiple, cross terms ✓

Common Mistakes

Avoid these frequent errors
  • Incorrect sign handling in middle terms
    Don't forget to apply negative signs to both terms when distributing = wrong signs throughout! Students often write (a-b)(c+4) as ac + 4a + bc + 4b, missing the negative on bc. Always carefully track each sign through every multiplication step.

Practice Quiz

Test your knowledge with interactive questions

\( (x+y)(x-y)= \)

FAQ

Everything you need to know about this question

How do I keep track of all the signs when expanding?

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Use the FOIL method systematically: First × First, Outer × Outer, Inner × Inner, Last × Last. Write each step: (ab)(c+4)=ac+4a+(b)(c)+(b)(4) (a-b)(c+4) = ac + 4a + (-b)(c) + (-b)(4) .

Why do some terms become positive and others negative?

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It depends on the signs being multiplied! Remember: positive × positive = positive, negative × negative = positive, but positive × negative = negative. Track each multiplication carefully.

What's the easiest way to check my expansion?

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Pick simple values like a=1, b=1, c=1 and substitute into both the original expression and your expanded form. If they give the same result, you're correct!

Do I always get four terms when expanding binomials?

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Usually yes, but sometimes terms can combine if they're like terms. In these problems, all four terms are different so you'll always have exactly four terms in the final answer.

How do I match the expressions to the right expansions?

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Expand each binomial product step by step, then compare term by term with the given options. Look for the same coefficients and signs in the same positions: ac term, a term, bc term, and constant term.

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