Join expressions of equal value
3(y+b)+4x
(3+4x)(y+b)
(4y+3)(x+b)
a.3y+3b+4x
b.4yx+4yb+3x+3b
c.3y+3b+4xy+4xb
To solve this problem, we'll follow these steps:
- Step 1: Expand each of the given expressions using the distributive property.
- Step 2: Simplify the resulting expressions.
- Step 3: Match the simplified expressions with options a, b, and c.
Now, let's work through each step:
Step 1: Start with the first expression 3(y+b)+4x.
Applying the distributive property: 3⋅y+3⋅b+4x=3y+3b+4x. This matches with option a: 3y+3b+4x.
Step 2: Consider the second expression (3+4x)(y+b).
Expanding using the distributive property, we get: 3(y+b)+4x(y+b)=3y+3b+4xy+4xb. This matches with option c: 3y+3b+4xy+4xb.
Step 3: Finally, expand the third expression (4y+3)(x+b).
Apply the distributive property: 4y(x+b)+3(x+b)=4yx+4yb+3x+3b. This matches with option b: 4yx+4yb+3x+3b.
Therefore, the matches are:
First expression matches option a
Second expression matches option c
Third expression matches option b
Therefore, the solution to the problem is 1-a, 2-c, 3-b.