Expand the Expression: (2x+y)(x+3) Using Distribution Method

(2x+y)(x+3)= (2x+y)(x+3)=

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00:00 Solve
00:04 Open parentheses properly, multiply each factor by each factor
00:14 Calculate the multiplications
00:45 And this is the solution to the question

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1

Understand the problem

(2x+y)(x+3)= (2x+y)(x+3)=

2

Step-by-step solution

To solve this problem, we'll apply the FOIL method for multiplying binomials:

  • First: Multiply the first terms in each binomial: (2x)(x)=2x2(2x)(x) = 2x^2.
  • Outer: Multiply the outer terms in the product: (2x)(3)=6x(2x)(3) = 6x.
  • Inner: Multiply the inner terms: (y)(x)=xy(y)(x) = xy.
  • Last: Multiply the last terms: (y)(3)=3y(y)(3) = 3y.

Next, we combine these results to form the expanded expression:

2x2+6x+xy+3y 2x^2 + 6x + xy + 3y .

Since terms 6x6x and xyxy are not like terms, they cannot be combined, resulting in the final expression:

2x2+xy+6x+3y 2x^2 + xy + 6x + 3y .

Upon reviewing the multiple-choice options, the correct answer is the expanded expression, choice 4: 2x2+xy+6x+3y 2x^2 + xy + 6x + 3y .

3

Final Answer

2x2+xy+6x+3y 2x^2+xy+6x+3y

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\( (3+20)\times(12+4)= \)

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