Insert the corresponding expression:
(23×7×5)a+2= \left(\frac{2}{3\times7\times5}\right)^{a+2}= (3×7×52)a+2=
2a+2(3×7×5)a+2 \frac{2^{a+2}}{\left(3\times7\times5\right)^{a+2}} (3×7×5)a+22a+2