Complete the Number 427?: Finding the Missing Digit for Divisibility by 9

Question

Complete the number so that it is divisible by 9 without a remainder:

427? 427?

Video Solution

Step-by-Step Solution

The problem asks us to find the digit represented by '?' in the number 427? 427? so that the entire number is divisible by 9.

To solve this problem, we will use the divisibility rule for 9, which states: A number is divisible by 9 if the sum of its digits is divisible by 9.

Let's calculate the sum of the known digits:

  • The digits are 4, 2, and 7.
  • Calculate the sum: 4+2+7=13 4 + 2 + 7 = 13 .

Now let's include the unknown digit, represented by x x , in the sum. The total sum of the digits will be S=4+2+7+x=13+x S = 4 + 2 + 7 + x = 13 + x .

We need 13+x 13 + x to be divisible by 9. So, find a value for x x such that 13+x0(mod9) 13 + x \equiv 0 \pmod{9} .

Let's check each value for x x from 0 to 9:

  • If x=0 x = 0 , 13+0=13 13 + 0 = 13 , not divisible by 9.
  • If x=1 x = 1 , 13+1=14 13 + 1 = 14 , not divisible by 9.
  • If x=2 x = 2 , 13+2=15 13 + 2 = 15 , not divisible by 9.
  • If x=3 x = 3 , 13+3=16 13 + 3 = 16 , not divisible by 9.
  • If x=4 x = 4 , 13+4=17 13 + 4 = 17 , not divisible by 9.
  • If x=5 x = 5 , 13+5=18 13 + 5 = 18 , which is divisible by 9.

Thus, the sum of the digits is divisible by 9 when x=5 x = 5 .

The correct digit to complete the number such that it is divisible by 9 is 5 5 .

Answer

5 5