Calculate the Perimeter of Rectangle ABCD with Sides 24 and 25 Units

Let's focus on triangle BCD in order to find side BC

We'll use the Pythagorean theorem and input the known data:

$BC^2+DC^2=BD^2$

$BC^2+24^2=25^2$

$BC^2=625-576=49$

Let's take the square root:

$BC=7$

Since in a rectangle, each pair of opposite sides are equal to each other, we can state that:

$DC=AB=24$

$BC=AD=7$

Now we can calculate the perimeter of the rectangle by adding all sides together:

$24+7+24+7=14+48=62$