Daniel bets on three games. In the first game, he lost three notes. In the second game, he lost 7 notes. In the third game, he won 2 notes and another £400. In total, Daniel left with the same amount of money he started with.
What is the value of each note?
To solve this problem, we'll follow these steps:
- Step 1: Identify the given information and express losses and gains as an equation.
- Step 2: Simplify the equation to solve for the value of a note x.
Now, let's work through each step:
Step 1: Define the total outcome equation given the losses and gains.
Daniel starts with an unknown amount equivalent to his final amount.
In the first game, he loses 3 notes, resulting in a loss of −3x.
In the second game, he loses 7 notes, resulting in a loss of −7x.
In the third game, he wins 2 notes, resulting in a gain of +2x, and he also wins an additional £400.
We equate the total changes to start with zero (final balance being the start):
−3x−7x+2x+400=0
Step 2: Simplify and solve for x.
Combine like terms:
−3x−7x+2x=−8x
Thus, the equation is:
−8x+400=0
Isolate x by subtracting 400 from both sides:
−8x=−400
Divide by −8 to solve for x:
x=−8−400
x=50
Therefore, each note is worth £50.
The value of each note is, therefore, £50.