Calculate Parallelogram Area: Using 6-Unit Height and 9-Unit Base with Perpendicular Lines

Question

ABCD is a parallelogram.

Angle ACB is equal to angle EBC.

BF = 6

CE = 9

BF is perpendicular to DE.

Calculate the area of the parallelogram.

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Video Solution

Solution Steps

00:00 Find the area of parallelogram ABCD
00:04 Alternate angles are equal between parallel lines
00:15 A line parallel to another line is also parallel to its extension
00:22 Quadrilateral ABCE is a parallelogram
00:27 Opposite sides are equal in a parallelogram
00:31 We'll use the formula to calculate the area of a parallelogram
00:35 Side(AB) multiplied by height (BF)
00:39 We'll substitute appropriate values and solve to find the area
00:42 And this is the solution to the question

Step-by-Step Solution

Given that angle ACB is equal to angle CBE, it follows that AC is parallel to BE

since alternate angles between parallel lines are equal.

As we know that ABCD is a parallelogram, AB is parallel to DC and therefore AB is also parallel to CE since it is a line that continues DC.

Given that AC is parallel to BE and, in addition, AB is parallel to CE, it can be argued that ABCE is a parallelogram and, therefore, each pair of opposite sides in a parallelogram are parallel and equal.

From this it is concluded that AB=CE=9

Now we calculate the area of the parallelogram ABCD according to the data.

SABCD=AB×BF S_{ABCD}=AB\times BF

We replace the data accordingly:

SABCD=9×6=54 S_{ABCD}=9\times6=54

Answer

54 cm²