Calculate (2/3)³: Finding the Cube of Two-Thirds

Question

(23)3= (\frac{2}{3})^3=

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the given fraction, which is 23\frac{2}{3}.
  • Step 2: Apply the formula for exponents applied to fractions, (ab)n=anbn \displaystyle(\frac{a}{b})^n = \frac{a^n}{b^n} .
  • Step 3: Calculate the cube of the numerator and the cube of the denominator separately.
  • Step 4: Write the results as a single fraction.

Now, let's work through each step:

Step 1: The problem provides the fraction 23\frac{2}{3}.

Step 2: Use the formula (ab)n=anbn(\frac{a}{b})^n = \frac{a^n}{b^n} for a=2a = 2, b=3b = 3, and n=3n = 3.

Step 3: We need to calculate 232^3 and 333^3:
- Calculate 23=2×2×2=82^3 = 2 \times 2 \times 2 = 8.
- Calculate 33=3×3×3=273^3 = 3 \times 3 \times 3 = 27.

Step 4: Writing these as a fraction gives 2333=827 \displaystyle \frac{2^3}{3^3} = \frac{8}{27} .

Therefore, the solution to the problem is 827\frac{8}{27}.

Answer

827 \frac{8}{27}