Plotting Functions with Parameters: Matching parameters

$y=x^2+10x$

Here we have a quadratic equation.

A quadratic equation is always constructed like this:

$y = ax²+bx+c$

Where a, b, and c are generally already known to us, and the X and Y points need to be discovered.

Firstly, it seems that in this formula we do not have the C,

Therefore, we understand it is equal to 0.

$c = 0$

a is the coefficient of X², here it does not have a coefficient, therefore

$a = 1$

$b= 10$

is the number that comes before the X that is not squared.

$a=1,b=10,c=0$

$y=2x^2-5x+6$

In fact, a quadratic equation is composed as follows:

y = ax²-bx-c

That is,

a is the coefficient of x², in this case 2.
b is the coefficient of x, in this case 5.
And c is the number without a variable at the end, in this case 6.

$a=2,b=-5,c=6$

$y=-2x^2+3x+10$

$a=-2,b=3,c=10$

$y=x^2$

$a=1,b=0,c=0$

$y=x^2-6x+4$

$a=1,b=-6,c=4$

$y=3x^2+4x+5$

$a=3,b=4,c=5$

$y=2x^2-3x-6$

$a=2,b=-3,c=-6$

$y=-5x^2+x$

$a=-5,b=1,c=0$

$y=2x^2+3$

$a=2,b=0,c=3$$$

$y=-4x^2-3x$

$a=-4,b=-3,c=0$

$y=-5+x^2$

$a=1,b=0,c=-5$

$y=-x^2+x+5$

$a=-1,b=1,c=5$

$y=x^2+x+5$

$a=1,b=1,c=5$

$y=-x-3x^2$

$a=-3,b=-1,c=0$

$y=-x^2+3x+40$

$a=-1,b=3,c=40$

$y=-2x^2-3x-4$

$a=-2,b=-3,c=-4$

$y=4+3x^2-x$

$a=3,b=-1,c=4$

$y=3x^2+4-5x$

$a=3,b=-5,c=4$

$y=6x+3x^2-4$

$a=3,b=6,c=-4$

$y=5x^2-4x-30$

$a=5,b=-4,c=-30$