The Quadratic Formula: Equations with variables on both sides

Solve the following equation:

$x^2+3x-3=x$

$x_1=1$, $x_2=-3$

What is the value of x?

$x^4-x^3=2x^2$

$x=-1,2,0$

$x^3=x^2+2x$

$x=0,-1,2$

Solve the following equation:

$3x^2-17x+28=x+4$

$x_1=4$, $x_2=2$

Solve the following equation:

$4x^2+9x-5=7-4x$

$x_1=\frac{3}{4}$ $x_2=-4$

Given the following equation, find its solution

$7x^2+3x+8=9x+3$

No solution

Solve the following equation:

$x^2+3x-4=2x^2$

No solution

Solve the following equation:

$-x^2+x-2=-2x^2-2x-4$

$x_1=-2,x_2=-1$

Solve the following equation:

$10x^2-65x+135=4x^2+13x-45$

$x_1=10$ $x_2=3$

Solve the following equation:

$-2x^2+6x-12=-4x^2+19x-5$

$x_1=7$, $x_2=-\frac{1}{2}$

Find X

$(3x+1)^2+8=12$

$x_1=\frac{1}{3},x_2=-1$

Solve the following equation:

$-(x+3)^2=4x$

$x_1=-1,x_2=-9$

Given the equation. Find its solution

$13x^2+4x=8(x+3)^2$

$x_1=10.21,x_2=-1.41$

Solve the following equation:

$\frac{x^3+1}{(x-1)^2}=x+4$

$x=3,\frac{1}{2}$

Solve the following equation:

$(x+2)^2=(2x+3)^2$

$x_1=-1,x_2=-\frac{5}{3}$

Solve the following equation:

$(x-4)^2+3x^2=-16x+12$

$x=-1$

Find X

$7x+1+(2x+3)^2=(4x+2)^2$

$\frac{1\pm\sqrt{33}}{8}$

Solve the equation

$2x^2-2x=(x+1)^2$

Answers a + b

Solve the following equation:

$(x-5)^2-5=10+2x$

$x_1=6+\frac{\sqrt{104}}{2},\\x_2=6-\frac{\sqrt{104}}{2}$

Solve the following equation:

$(x-5)^2-5=-12+2x$

$x_1=8,x_2=4$