Volume of a Orthohedron: Worded problems

Let's denote the initial cube's edge length as x,

The formula for the volume of a cube with edge length b is:

$V=b^3$

therefore the volume of the initial cube (meaning before increasing its edge) is:

$V_1=x^3$

Now we'll increase the cube's edge by a factor of 6, meaning the edge length is now: 6x, therefore the volume of the new cube is:

$V_2=(6x)^3=6^3x^3$

where in the second step we simplified the expression for the new cube's volume using the power rule for multiplication in parentheses:

$(z\cdot y)^n=z^n\cdot y^n$

and we applied the power to each term in the parentheses multiplication,

Next we'll answer the question that was asked - "By what factor did the cube's volume increase", meaning - by what factor do we multiply the old cube's volume (before increasing its edge) to get the new cube's volume?

Therefore to answer this question we simply divide the new cube's volume by the old cube's volume:

$\frac{V_2}{V_1}=\frac{6^3x^3}{x^3}=6^3$

where in the first step we substituted the expressions for the volumes of the old and new cubes that we got above, and in the second step we reduced the common factor between the numerator and denominator,

Therefore we got that the cube's volume increased by a factor of -$6^3$when we increased its edge by a factor of 6,

therefore the correct answer is b.

We use a formula to calculate the volume: height times width times length.

We rewrite the exercise using the existing data:

$21\times(14+30x)\times15=$

We use the distributive property to simplify the parentheses.

We multiply 21 by each of the terms in parentheses:

$(21\times14+21\times30x)\times15=$

We solve the multiplication exercise in parentheses:

$(294+630x)\times15=$

We use the distributive property again.

We multiply 15 by each of the terms in parentheses:

$294\times15+630x\times15=$

We solve each of the exercises in parentheses to find the volume:

$4,410+9,450x$